Scores had a Mean of 82 and a Standard Deviation of 5 0. Find a z score for x =81 and x = 68 Z- score for 81 -0.2 z- score for 68 28 1. Find the percent of scores that were above 86. Z score for 86 Table score for 86

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**Transcription for Educational Website**

**Scores Analysis with Mean and Standard Deviation**

The analysis provides calculations of z-scores and the percentage of scores above a certain threshold, using the following statistical parameters:
- Mean (average) of scores: 82
- Standard Deviation: 5

**Questions and Solutions:**

6. **Find a z-score for x = 81 and x = 68**

   - *Z-score for 81*: -0.2
   - *Z-score for 68*: -2.8

7. **Find the percent of scores that were above 86.**

   - Z-score for 86: _______
   - Table score for 86: _______

To solve these, students are expected to apply the standard z-score formula:

\[ z = \frac{(x - \text{mean})}{\text{standard deviation}} \]

Where \( x \) is the raw score, the mean is the average score (82), and the standard deviation is 5. The z-scores indicate how many standard deviations an element is from the mean.
Transcribed Image Text:**Transcription for Educational Website** **Scores Analysis with Mean and Standard Deviation** The analysis provides calculations of z-scores and the percentage of scores above a certain threshold, using the following statistical parameters: - Mean (average) of scores: 82 - Standard Deviation: 5 **Questions and Solutions:** 6. **Find a z-score for x = 81 and x = 68** - *Z-score for 81*: -0.2 - *Z-score for 68*: -2.8 7. **Find the percent of scores that were above 86.** - Z-score for 86: _______ - Table score for 86: _______ To solve these, students are expected to apply the standard z-score formula: \[ z = \frac{(x - \text{mean})}{\text{standard deviation}} \] Where \( x \) is the raw score, the mean is the average score (82), and the standard deviation is 5. The z-scores indicate how many standard deviations an element is from the mean.
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