Draw the shear and moment diagrams for the cantilever beam shown and determine the maximum absolute value of the shear and bending moment. Indicate the degree of each curve. You may use the method of sections, area method, or both. 15 kN/m 8 kN 5 kN/m A В 20 kN/m 8 kN/m E 2 m →e 3 m 6 m

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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SHEAR AND BENDING MOMENT DIAGRAM

- GET THE GIVEN, WHAT IS ASKED, AND THE ANSWER.

- MAKE A PROPER FREE BODY DIAGRAM. (IT DOES HAVE THE GREATER POINTS IN THIS ACTIVITY)

- YOUR SUB ANSWERS MUST BE IN 6 DECIMAL PLACES.

- YOUR FINAL ANSWER MUST BE IN 4 DECIMAL PLACES.

- TELL THE DIRECTION AND WHETHER IT IS TENSILE OR COMPRESSION.

- WRITE YOUR SOLUTION PROPERLY (EASY TO UNDERSTAND).

- I PREPARED A SAMPLE PROBLEM SO THAT YOU CAN FOLLOW THE STEPS ON HOW TO SOLVE IT.
 
Sample Problem 1
Method of Areas
Draw the shear force and bending moment diagrams
for the beam and determine the maximum absolute
value of the shear and bending moment. Indicate the
degree of each curve.
5. If the load diagram is a polynomial of degree n, then the
shear force diagram is a polynomial of degree (n+ 1),
and the bending moment diagram is a polynomial of
degree (n + 2).
2 kN/m
50 kN · m
LOAD (w)
SHEAR FORCE (V)
BENDING MOMENT (M)
В
0°
1°
2°
-5 m
-5 m
1°
2°
3°
2°
3°
4°
2. Method of Sections
3
2 kN/m
50 kN · m
n°
(n + 1)°
(n + 2)°
Sample Problem 1
-5 m
Given:
Required: e, Mnox
Solution:
1
3. Method of Areas
5
V and m Diograms 2 Sm
z kn
jokN
Sample Problem 3
Draw the shear force and bending moment diagrams
for the beam and determine the maximum absolute
Ay
の2M、0
-o(25) -50+ Cy (^) ~O
Cy: 7SKN ↑
Au + 75 - 10 O
2 5KN 1,
value of the shear and bending moment. Indicate the
degree of each curve.
そ
8 kN
8 kN
15 kN/m
20 kN m
1
2. Method of Sections
3
5
2 kN/m
I50 kN - m
В
Sample Problem 1
• Consider
-5 m-
|2%
2/en
* 0.75 m--
0.25 m
-1 m
1m
-1 m
$2Fy :0
25 - 2x -V :0
V: -2x 42 5,
8 kN
8 kN
1
3. Method of Areas
4
15 kN/m
-2'5 x + 2x () +M-0
At X:0
V = 2.5KN
M= 0
20 kN · m
M= -* +25X
Sample Problem 3
V= -75 kM
M: -12-5 KN m
AI X=Sm
В
Given:
Required: v Moox
Solution:
v ond M Diagnome
--0.75 m-
0.25 m
-1m
1 m
-1 m
2. Method of Sections
4
2 kN/m
Ax
50 kN · m
ト%
の 2M、:0
Dy (3)-6(=)-8() - 20 - 15 (35)-D
Sample Problem 1
wit
a Concider
-5 m
-5 m
0-25m
2kN /m
A,132 Ib47 - 8-る-15-0
25 - 10 -V :
,Sר- <V
Du 32.1647 KN 1
Ay:-1 1467KN 1
2SKN
D SM: 0
m -25(x)-50 +10(x-25)0
At X: Sm
V:-75KN
M: 375kn m
M- 25x -50 +1OX -25. O
0 :5א ירwA
Mュ-15x *15。
V. 7-5KN
8 kN
8 kN
At x: 10m
1
2
3. Method of Areas
15 kN/m
20 kN · m,
Sample Problem 3
• Bending moment Diagram-
MAL:0
MAPIMAL t0+ 0
BE
D
4 Shear Fore
Diogrom
VAL
| 2. Method of Sections
3
321 6G667KN
4
5
2 kN/m
50 kN - m
--0.75 m-.
0.25 m
1m
*1 m
Sample Problem 1
15KN
MoR = MOLto = -1647 khim
MEL MaR (-91wiX25)* v(kN)
ME
5 m
VAR' VAL-I I
V= -Zx 12.5
M: -x42 SX
5 m
Vo: VAR 10 =- 1167 KN
VoR: VoL -8: 91647 ky
usラメラ0
V : 2 SkN
"ER MEL+20: 16-541716N m
M: -12.5KN m
M: -75x + 75
M: 37.5KNn
V(kN)
(m)
V.-15
Vray: 71667
Mray : 16 5blm
V. -7SKN
McR
Vee:VEL4O: -41とN
x(m)
レ
V. -15トト
-75
X 1 25m
MoR-MOL= -7skym
315
25
M(kNm)
M(kNm)
M. 1S625 AN m
At 12sm
x (т)
x(m)
Desmos Groph
= 37.SN
Veし: Voe - (sXン:0
VER VEL + Ó =0
-12-5
Transcribed Image Text:Sample Problem 1 Method of Areas Draw the shear force and bending moment diagrams for the beam and determine the maximum absolute value of the shear and bending moment. Indicate the degree of each curve. 5. If the load diagram is a polynomial of degree n, then the shear force diagram is a polynomial of degree (n+ 1), and the bending moment diagram is a polynomial of degree (n + 2). 2 kN/m 50 kN · m LOAD (w) SHEAR FORCE (V) BENDING MOMENT (M) В 0° 1° 2° -5 m -5 m 1° 2° 3° 2° 3° 4° 2. Method of Sections 3 2 kN/m 50 kN · m n° (n + 1)° (n + 2)° Sample Problem 1 -5 m Given: Required: e, Mnox Solution: 1 3. Method of Areas 5 V and m Diograms 2 Sm z kn jokN Sample Problem 3 Draw the shear force and bending moment diagrams for the beam and determine the maximum absolute Ay の2M、0 -o(25) -50+ Cy (^) ~O Cy: 7SKN ↑ Au + 75 - 10 O 2 5KN 1, value of the shear and bending moment. Indicate the degree of each curve. そ 8 kN 8 kN 15 kN/m 20 kN m 1 2. Method of Sections 3 5 2 kN/m I50 kN - m В Sample Problem 1 • Consider -5 m- |2% 2/en * 0.75 m-- 0.25 m -1 m 1m -1 m $2Fy :0 25 - 2x -V :0 V: -2x 42 5, 8 kN 8 kN 1 3. Method of Areas 4 15 kN/m -2'5 x + 2x () +M-0 At X:0 V = 2.5KN M= 0 20 kN · m M= -* +25X Sample Problem 3 V= -75 kM M: -12-5 KN m AI X=Sm В Given: Required: v Moox Solution: v ond M Diagnome --0.75 m- 0.25 m -1m 1 m -1 m 2. Method of Sections 4 2 kN/m Ax 50 kN · m ト% の 2M、:0 Dy (3)-6(=)-8() - 20 - 15 (35)-D Sample Problem 1 wit a Concider -5 m -5 m 0-25m 2kN /m A,132 Ib47 - 8-る-15-0 25 - 10 -V : ,Sר- <V Du 32.1647 KN 1 Ay:-1 1467KN 1 2SKN D SM: 0 m -25(x)-50 +10(x-25)0 At X: Sm V:-75KN M: 375kn m M- 25x -50 +1OX -25. O 0 :5א ירwA Mュ-15x *15。 V. 7-5KN 8 kN 8 kN At x: 10m 1 2 3. Method of Areas 15 kN/m 20 kN · m, Sample Problem 3 • Bending moment Diagram- MAL:0 MAPIMAL t0+ 0 BE D 4 Shear Fore Diogrom VAL | 2. Method of Sections 3 321 6G667KN 4 5 2 kN/m 50 kN - m --0.75 m-. 0.25 m 1m *1 m Sample Problem 1 15KN MoR = MOLto = -1647 khim MEL MaR (-91wiX25)* v(kN) ME 5 m VAR' VAL-I I V= -Zx 12.5 M: -x42 SX 5 m Vo: VAR 10 =- 1167 KN VoR: VoL -8: 91647 ky usラメラ0 V : 2 SkN "ER MEL+20: 16-541716N m M: -12.5KN m M: -75x + 75 M: 37.5KNn V(kN) (m) V.-15 Vray: 71667 Mray : 16 5blm V. -7SKN McR Vee:VEL4O: -41とN x(m) レ V. -15トト -75 X 1 25m MoR-MOL= -7skym 315 25 M(kNm) M(kNm) M. 1S625 AN m At 12sm x (т) x(m) Desmos Groph = 37.SN Veし: Voe - (sXン:0 VER VEL + Ó =0 -12-5
Draw the shear and moment diagrams for the cantilever beam shown and determine the maximum absolute value of the shear
and bending moment. Indicate the degree of each curve. You may use the method of sections, area method, or both.
15 kN/m
8 kN
5 kN/m
A
В
20 kN/m
8 kN/m
E 2 m →e
3 m
6 m
Transcribed Image Text:Draw the shear and moment diagrams for the cantilever beam shown and determine the maximum absolute value of the shear and bending moment. Indicate the degree of each curve. You may use the method of sections, area method, or both. 15 kN/m 8 kN 5 kN/m A В 20 kN/m 8 kN/m E 2 m →e 3 m 6 m
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