*46. The parallel axis theorem provides a useful way to calculate the moment of inertia I about an arbitrary axis. The theorem states that I = Im + Mh², where Im is the moment of inertia of the object relative to an axis that passes through the center of mass and is parallel to the axis of interest, M is the total mass of the object, and h is the perpendicular distance between the two axes. Use this theorem and information to determine an expression for the moment of inertia of a solid cylinder of radius R relative to an axis that lies on the surface of the cylinder and is perpendicular to the circular ends.

*46. The parallel axis theorem provides a useful way to calculate the moment of inertia I about an arbitrary axis. The theorem states that I = Im + Mh², where Im is the moment of inertia of the object relative to an axis that passes through the center of mass and is parallel to the axis of interest, M is the total mass of the object, and h is the perpendicular distance between the two axes. Use this theorem and information to determine an expression for the moment of inertia of a solid cylinder of radius R relative to an axis that lies on the surface of the cylinder and is perpendicular to the circular ends.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A 0.8 m Mass Moment of Inertia. For each system, find the mass moment of inertia about an axis going through Point A (perpendicular to the paper). c. Point A is in the upper left corner of the object shown. It has a uniform area density of 120 kg/m². 0.4 m 0.8 m A - 0.4 m 120 kg/m² 0.4 m 0.4 m d. The system is 15kg uniform isosceles triangle with a height of 0.33m and a base of 0.26m. Point A is at the lower left corner of the triangle. m = 15 kg 0.26 m 0.33 m
Determine the moment of inertia about the x-axis of each of the areas shown in Figure P9–1. (Hey whatsup, Could you please help me with this solution,I appreciate it)
How do I solve this question?
An ice skater has a moment of inertia of 4.5 kgm2 when her arms are outstretched. With her arms outstretched she is spinning 3.8 radians per second. If she pulls her arms in and decreases her moment of inertia to 2.4 kgm2, how fast is she spinning? A: 7.1 radians/second B: 2.8 radians/second C: 17.1 radians/second D: 6.2 radians/second E: 2.0 radians/second
Four identical particles (mass of each = 0.40 kg) are placed at the vertices of a rectangle (2.0 m × 3.0 m) and held in those positions by four light rods which form the sides of the rectangle. What is the moment of inertia of this rigid body about an axis that passes through the mid-points of the longer sides and is parallel to the shorter sides? Group of answer choices 2.7 kg⋅m2 3.6 kg⋅m2 1.6 kg⋅m2 3.1 kg⋅m2 4.1 kg⋅m2
2. In the thin plate shown below, the material has a mass per unit area of 20 kg/m² (that is, instead of thinking of this as a volume with a thickness, we're just focused on the 2D area of the shape). What is the moment of inertia of this plate around the pivot point, O? 50 mm 400 mm 150 mm 150 mm 400 mm
In the figure below, what is the moment of inertia of the system about the y-axis if m = 2.0 kg and a = 1.0 m? Assume that the connecting sticks are massless. * a a a a 4.0 kg-m^2. 4.8 kg-m^2. 9.6 kg-m^2. 10.3 kg-m^2. 12.0 kg-m^2.
Physics Angular Motion
A massless frame in the shape of a coff square 6.5 m on a side has a 17.6-kg ball at each corner. 1What is the moment of inertia (in kg m) of the four balls about an axis perpendicular to the plane of the square and passing through the corner marked O? From your answer without a decimal place. kg kg kg Un maecs sin mana es la forma de un cuadrado colt 6.5 m de lado tansle una bola de 176 kg en cadu esquina Cual es el modsento de ioereia (en kg m de la CORro bolas alrededor de uo eje perpendicular al plano del cuadindo y paia por la esquina aarcada con O Dr su repuenta sn lagar decamal kg
16. Y is that? Consider the following composite body as shown. The composite body is made up of uniform rods each of mass M and length L. The moment of inertia of each rod through its center of mass and perpendicular to its length is Iem = ML². What is the moment of inertia of the composite object when it is allowed to rotate about the Y axis as shown? Assume that the Y axis is exactly in the middle of the composite body. A. M L² B. ML? c. 등ML2 D. ML? 8.
Q2. A thin square wooden slab was freely rotating on the frictionless surface (like an ice) with angular velocity i. The length of one side of the slab was L. The thickness of the slab was h. The density of the slab is p. Answer the following questions. ht Wi (a) What is the moment of inertia of this rotating slab? (b) What is the kinetic energy of this rotating slab?
Q6