Q10. Moment of inertia of a solid cylinder of mass M, height I and radius R about an axis (shown in the figure by dashed line) passing through its centre of mass and perpendicular to its symmetry axis is (a) –MR? + MI? 4 12 MR (e) – MR* +M* +-MI? 8 1 MR² MI? 12 (d) 극MR' +MI MI² 4
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- A 8 kg point mass is at coordinates (8m, 4m), a 2 kg mass is at (-9,6) and a 3kg mass is at (x,y) of (5,-9) . Find the moment of inertia about the x axis. Find 1z=______ kg-m2i need the answer quicklyCan you please help me answer the last three parts of this same problem. Question 4: What is the skater's angular momentum?please answer in kg m^2 /s Question 5: The skater pulls his arms in to his chest and now he can be approximted as just a cylinder. What is his new moment of inertia? Please answer in kg m^2 Question 6: How fast is he spinning now that his arms are pulled in? Assume no external torque acts on him as he spins. Please answer in rad/s
- Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 m. sin() cos() tan() 7 8 9 HOME cotan() asin() acos() E 4 5 atan() acotan() sinh() 1 3 cosh() tanh() cotanh() END ODegrees O Radians Vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) Now calculate the moment of inertia of the skater (in kg m?) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated at the ends.A 1.10-kg particle moves in the xy plane with a velocity of Need Help? Read It = (3.70 1-3.70 ĵ) m/s. Determine the angular momentum of the particle about the origin when its position vector is = (1.50 î+ 2.20 ĵ) m. k) kg - m²/s Watch ItA 7 kg point mass is at coordinates (5 m, 5 m), a 4 kg mass is at (-5,7) and a 5kg mass is at (x,y) of (4,-7). Find the moment of inertia about the x axis. Find Iz = __________ kg-m2
- Suppose partial melting of the polar ice capsincreases the moment of inertia of the Earth from 0.331 MERE2 to0.332 MERE2. (a) Would the length of a day (the time required forthe Earth to complete one revolution about its axis) increase ordecrease? Explain. (b) Calculate the change in the length of a day.Give your answer in secondsTwo astronauts (figure), each having a mass of 76.0 kg, are connected by a d = 11.0-m rope of negligible mass. They are isolated in space, orbiting their center of mass at speeds of 5.50 m/s. CM d (a) Treating the astronauts as particles, calculate the magnitude of the angular momentum of the two-astronaut system. |kg · m²/s (b) Calculate the rotational energy of the system. kJ (c) By pulling on the rope, one astronaut shortens the distance between them to 5.00 m. What is the new angular momentum of the system? |kg · m²/s (d) What are the astronauts' new speeds? m/s (e) What is the new rotational energy of the system? kJ (f) How much chemical potential energy in the body of the astronaut was converted to mechanical energy in the system when he shortened the rope? kJ Need Help? Read It Master ItThe Earth has a mass m = 6.0 x1024 kg, and a radius R = 6400 km. It rotates about its own axis and it orbits around the sun at a distance d = 1.5x1011 m. What is its total angular momentum of Earth due to: Its spinning motion about its Its orbital motion about the
- The moment of inertia of an object about a certain axis is 1.2 kg-m2. Initially the object is at rest, and then it is accelerated at a constant rate of 25 rad-s-2. Determine the time required for the object to achieve a rotational kinetic energy of 1.50 kJ.3. A person (treated as a red point object) of mass m₁ 50 kg is attached to a rod of length L = 1 m and mass M = 20 kg. Together, they are rotating counterclockwise around a pivot (green), with angular speed w = 2 rad/s: m2 = M, L Vo = m1 A ball (purple point object) of mass m₂ = 5 kg is thrown with speed vo 30 m/s at the person, who catches the ball just as the bar is oriented horizontally during its rotation (as seen in the figure). If the bar and person are stationary after the catch, how far away from the pivot was the ball thrown (that is, what is the length of the dashed black line)? Hint: Use the conservation of angular momentum.