A miter saw has an operating speed of 1500 rpm (157.08 rad/s). The blade and motor armature have a combined weight of 3 lbs and a radius of 1 inch. I = mr2 (Impulse and Momentum) - What is the time required for the bearing friction (torque =.015 in lbs) alone to stop the blade? - What is the torque a braking system would need to apply to stop the blade in just .25 seconds?

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A miter saw has an operating speed of 1500 rpm (157.08 rad/s).
The blade and motor armature have a combined weight of 3 lbs and
a radius of 1 inch. I = mr² (Impulse and Momentum)
What is the time required for the bearing friction (torque = .015 in lbs)
alone to stop the blade?
What is the torque a braking system would need to apply to stop the
blade in just .25 seconds?
Transcribed Image Text:A miter saw has an operating speed of 1500 rpm (157.08 rad/s). The blade and motor armature have a combined weight of 3 lbs and a radius of 1 inch. I = mr² (Impulse and Momentum) What is the time required for the bearing friction (torque = .015 in lbs) alone to stop the blade? What is the torque a braking system would need to apply to stop the blade in just .25 seconds?
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