A 0.8 m Mass Moment of Inertia. For each system, find the mass moment of inertia about an axis going through Point A (perpendicular to the paper). c. Point A is in the upper left corner of the object shown. It has a uniform area density of 120 kg/m². 0.4 m 0.8 m A - 0.4 m 120 kg/m² 0.4 m 0.4 m d. The system is 15kg uniform isosceles triangle with a height of 0.33m and a base of 0.26m. Point A is at the lower left corner of the triangle. m = 15 kg 0.26 m 0.33 m
A 0.8 m Mass Moment of Inertia. For each system, find the mass moment of inertia about an axis going through Point A (perpendicular to the paper). c. Point A is in the upper left corner of the object shown. It has a uniform area density of 120 kg/m². 0.4 m 0.8 m A - 0.4 m 120 kg/m² 0.4 m 0.4 m d. The system is 15kg uniform isosceles triangle with a height of 0.33m and a base of 0.26m. Point A is at the lower left corner of the triangle. m = 15 kg 0.26 m 0.33 m
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0.8 m
Mass Moment of Inertia. For each system, find the mass moment of inertia about an
axis going through Point A (perpendicular to the paper).
c. Point A is in the upper left corner of the object shown. It has a uniform area
density of 120 kg/m².
0.4 m
0.8 m
A
- 0.4 m
120 kg/m²
0.4 m
0.4 m
d. The system is 15kg uniform isosceles triangle with a height of 0.33m and a base
of 0.26m. Point A is at the lower left corner of the triangle.
m = 15 kg
0.26 m
0.33 m"
Transcribed Image Text:A
0.8 m
Mass Moment of Inertia. For each system, find the mass moment of inertia about an
axis going through Point A (perpendicular to the paper).
c. Point A is in the upper left corner of the object shown. It has a uniform area
density of 120 kg/m².
0.4 m
0.8 m
A
- 0.4 m
120 kg/m²
0.4 m
0.4 m
d. The system is 15kg uniform isosceles triangle with a height of 0.33m and a base
of 0.26m. Point A is at the lower left corner of the triangle.
m = 15 kg
0.26 m
0.33 m
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