43.μ1. (Confidence interval for µ given 02²) Determine the confidence interval [01, 02] μ,0.95 withconfidence level y 0.95 for the mean μ of a normal distribution with variance σ² = 4,using a samples of n = 400 values with sample mean = 3.=2. (Confidence interval for μ with unknown σ²) Six independent measurements are takenfrom a normal population. The sample has values x1 = 21, x2=19, x322, x4 = 20,x5 = 18, and x6 = 24. Find a 99% confidence interval for the mean.

Question 1)We are given the following:sample mean , x̄ = 3sample size, n = 400confidence level, c =…

Answered: 43. μ 1. (Confidence interval for µ…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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n= 50 Mean, = ΣΧ = 1570/50 = 31.4 Standard deviation, o = = 20.41 Using empirical rule, 68% of the data falls within one standard deviation, 95% within two standard deviations, and 99.7% within three standard deviations from the mean. => 68% of data falls between e + o = 31.4 + 20.41 = (10.99, 51.81) => 95% of the data falls between e ± 2 * o = 31.4 + 2*20.41 = (-9.42, 72.22) => 99.7% of the data falls between + 3 * o = 31.4 +3*20.41 = (-29.83, 92.63) QUESTIONS: 1. How does answers in 68%, 95%, and 99.7% of data compare, respectively? 2. How does it support the conclusion you reached in question 1? Explain thoroughly.

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