As a quality control manager, you have been measuring the pressure level provided by a newly installed pump which are purchased from new manufacturer. The mean pressure maintained by old pump was 150.00 kPa. The manufacturer of the new pump claims that the pressure will be improved after installing the new pump. You have been tasked to ensure that the new pump is better. DATA 96.17 128.32 169.54 167.06 108.02 125.95 152.66 106.58 156.05 134.51 108.77 129.19 93.88 139.16 119.73 176.95 175.1 131.27 182.63 123.95 116.56 91.28 133.55 117.12 217.31 147.25 104.32 159.96 99.02 104.7 124.9 131.31 98.18 66.54 172.01 46.32 140.98 158.39
Continuous Probability Distributions
Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could count from 0 to a trillion seconds, billion seconds, so on indefinitely. A discrete probability distribution consists of only a countable set of possible values.
Normal Distribution
Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a great idea as the sensitivity of the scale would get reduced if the range is too large. At the same time, if we keep the upper limit too low, it may not be usable for a large percentage of the population!
H0 : =150.00 kPa
H1 :>150.00 kPa
b) α= 0.01;
sample variance : 1300 (freq. table )
sample deviation : 36.0555 (freq. table )
Calculation of Data
Mean of the results= = 6700/50 =134
Mid
Range = (217.32-46.32) = 171
Modal Class= Class 121-145 with the highest frequency of 15
Median of the sorted set of data = 132.25
Sample variance S o= 1300
Sample deviation: S =36.55
![As a quality control manager, you have been measuring the pressure level provided by a newly
installed
dund
which are purchased from new manufacturer. The mean pressure maintained by the
old pump was 150.00 kPa. The manufacturer of the new pump claims that the pressure will be
improved after installing the new pump. You have been tasked to ensure that the new pump is
better.
DATA
96.17
128.32
169.54
167.06
108.02
125.95
152.66
106.58
156.05
134.51
108.77
129.19
93.88
139.16
119.73
176.95
175.1
131.27
182.63
123.95
116.56
91.28
133.55
117.12
217.31
147.25
104.32
159.96
99.02
104.7
124.9
131.31
98.18
66.54
172.01
46.32
140.98
158.39
cumula Relative
Mid point (X m) =
freque tive
interval boundary ncy (f) frequen
Class
Class
frequency
f x Xm
lower + upper
су
Ef
2
46+70
46-70
45.5-70.5
= 0. 04
50
= 58
2 x 58 = 116
2
4
71-95
70.5-95.5
= 0. 08
50
83
332
12
96-120
95.5-120.5 12
18
= 0. 24
50
108
1296
15
121-145
120.5-145.5 15
33
= 0. 30
50
133
1995
9
146-170
= 0. 18
50
158
1422
145.5-170.5 9
42
5
171-195
170.5-195.5 5
47
= 0. 10
50
183
915
196-220
195.5-220.5 3
50
3
0.06
208
624
50
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9fd72755-fbcd-4bf5-b9e3-e08fe5879c40%2Fc3646b04-d62f-475a-875b-b2ed618f22a9%2F8zrnp18_processed.png&w=3840&q=75)
![D) CREATE HYPOTHESIS TESTING
SAMPLE MEAN FROM (FREQUENCY TABLE)
SIGNIFICANCE LEVEL: 0.01
SAMPLE STANDARD DEVIATION (FREQUENCY TABLE)
CONFIDENCE INTERVAL 90%
THIS DATA HAS NO OUTLIERS
(EXPLAIN HYPOTHESIS)
SHOW CRITICAL VALUE AND TEST RESULTS](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9fd72755-fbcd-4bf5-b9e3-e08fe5879c40%2Fc3646b04-d62f-475a-875b-b2ed618f22a9%2Fdn0rfl_processed.png&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Claim:- The pressure will be improved after installing the new pump.
The hypothesis is,
The test statistic is,
So,
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