Sample size: 117 R (correlation coefficient) = 0.8448 R-sq = 0.7136788 Estimate of error standard deviation: 204.45117 Parameter estimates (rounded): Parameter Intercept Slope O-52.649 and the variety of T listed below: O 0.5282 O 0.5012 Estimate 0.5383 47.819 O 0.5582 0.6237 Std. Err. 62.855 0.0519 DF T.01,115= 2.35921, T.02,115-2.07731, T.01,116-2.35892 T.02,116=2.07710, T.01,117-2.35864 What is the approximate lower level of the 98% confidence interval on the slope? T-Stat 0.76079 16.2187 P-Value 0.4483 <0.0001
Sample size: 117 R (correlation coefficient) = 0.8448 R-sq = 0.7136788 Estimate of error standard deviation: 204.45117 Parameter estimates (rounded): Parameter Intercept Slope O-52.649 and the variety of T listed below: O 0.5282 O 0.5012 Estimate 0.5383 47.819 O 0.5582 0.6237 Std. Err. 62.855 0.0519 DF T.01,115= 2.35921, T.02,115-2.07731, T.01,116-2.35892 T.02,116=2.07710, T.01,117-2.35864 What is the approximate lower level of the 98% confidence interval on the slope? T-Stat 0.76079 16.2187 P-Value 0.4483 <0.0001
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Please help
![Given the following output regression, relating to predicting housing prices, based on square footage:
Simple linear regression results:
Dependent Variable: PRICE
Independent Variable: SQFT
PRICE = 47.819305 +0.61366683 SQFT
Sample size: 117
R (correlation coefficient) 0.8448
R-sq = 0.7136788
Estimate of error standard deviation: 204.45117
Parameter estimates (rounded):
Slope
Parameter
Intercept
Estimate
47.819
0.6237
and the variety of T listed below:
Std. Err.
62.855
0.0519
DF
T-Stat
0.76079
16.2187
P-Value
0.4483
T.01,115= 2.35921, T.02,115-2.07731, T.01.116-2.35892
T.02.116 2.07710, T.01.117=2.35864
What is the approximate lower level of the 98% confidence interval on the slope?
<0.0001](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8daeabfb-08fc-4e08-b5f3-009f3913f10d%2Ff2ed60a2-dda4-4c12-9162-13b176f45804%2Fn3fxu9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the following output regression, relating to predicting housing prices, based on square footage:
Simple linear regression results:
Dependent Variable: PRICE
Independent Variable: SQFT
PRICE = 47.819305 +0.61366683 SQFT
Sample size: 117
R (correlation coefficient) 0.8448
R-sq = 0.7136788
Estimate of error standard deviation: 204.45117
Parameter estimates (rounded):
Slope
Parameter
Intercept
Estimate
47.819
0.6237
and the variety of T listed below:
Std. Err.
62.855
0.0519
DF
T-Stat
0.76079
16.2187
P-Value
0.4483
T.01,115= 2.35921, T.02,115-2.07731, T.01.116-2.35892
T.02.116 2.07710, T.01.117=2.35864
What is the approximate lower level of the 98% confidence interval on the slope?
<0.0001
![Sample size: 117
R (correlation coefficient) = 0.8448
R-sq = 0.7136788
Estimate of error standard deviation: 204.45117
Parameter estimates (rounded):
Parameter
Intercept
Slope
O -52.649
and the variety of T listed below:
O 0.5282
O 0.5012
Estimate
O 0.5383
47.819
O 0.5582
0.6237
Std. Err.
62.855
0.0519
DF T-Stat
T.01,115= 2.35921, T.02,115-2.07731, T.01,116-2.35892
T.02,116=2.07710, T.01,117-2.35864
What is the approximate lower level of the 98% confidence interval on the slope?
0.76079
16.2187
P-Value
0.4483
<0.0001](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8daeabfb-08fc-4e08-b5f3-009f3913f10d%2Ff2ed60a2-dda4-4c12-9162-13b176f45804%2F0wh95p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sample size: 117
R (correlation coefficient) = 0.8448
R-sq = 0.7136788
Estimate of error standard deviation: 204.45117
Parameter estimates (rounded):
Parameter
Intercept
Slope
O -52.649
and the variety of T listed below:
O 0.5282
O 0.5012
Estimate
O 0.5383
47.819
O 0.5582
0.6237
Std. Err.
62.855
0.0519
DF T-Stat
T.01,115= 2.35921, T.02,115-2.07731, T.01,116-2.35892
T.02,116=2.07710, T.01,117-2.35864
What is the approximate lower level of the 98% confidence interval on the slope?
0.76079
16.2187
P-Value
0.4483
<0.0001
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