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MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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### Hypothesis Testing: Energy Levels and Diet

**Question 3 SLO**

**Objective:** Identify the null hypothesis, alternative hypothesis, test statistic, p-value, initial and final conclusion.

**Problem Statement:** Test the claim that less than 45% of the people following a particular diet will experience increased energy. Of 81 randomly selected subjects who followed the diet, 42 noticed an increase in their energy level.

---

To solve this, we need to follow the steps of hypothesis testing. Here's the breakdown:

1. **Formulate Hypotheses:**
   - **Null Hypothesis (H₀):** \( p \geq 0.45 \)
     - This indicates that 45% or more of the people following the diet will experience increased energy.
   - **Alternative Hypothesis (H₁):** \( p < 0.45 \)
     - This indicates that less than 45% of the people following the diet will experience increased energy.

2. **Collect Data:**
   - Sample size (n): 81
   - Number of subjects experiencing increased energy (x): 42
   - Sample proportion (\( \hat{p} \)): \( \frac{42}{81} \approx 0.5185 \)

3. **Calculate the Test Statistic:**
   - The test statistic for a proportion is calculated using the formula:
     \[
     z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}
     \]
     where \( p_0 \) is the hypothesized population proportion (0.45).

4. **Determine the p-value:**
   - The p-value indicates the probability of obtaining a test statistic at least as extreme as the one observed, assuming the null hypothesis is true. This value helps us decide if we should reject the null hypothesis.

5. **Make a Decision:**
   - Compare the p-value with the chosen significance level (α), often set at 0.05.
     - If p-value < α, reject the null hypothesis.
     - Otherwise, do not reject the null hypothesis.

6. **Conclusion:**
   - State your initial conclusion based on the p-value.
   - Provide final conclusion: whether there is sufficient evidence to support the claim that less than 45% of the people following the diet will experience increased energy.

---

By
Transcribed Image Text:### Hypothesis Testing: Energy Levels and Diet **Question 3 SLO** **Objective:** Identify the null hypothesis, alternative hypothesis, test statistic, p-value, initial and final conclusion. **Problem Statement:** Test the claim that less than 45% of the people following a particular diet will experience increased energy. Of 81 randomly selected subjects who followed the diet, 42 noticed an increase in their energy level. --- To solve this, we need to follow the steps of hypothesis testing. Here's the breakdown: 1. **Formulate Hypotheses:** - **Null Hypothesis (H₀):** \( p \geq 0.45 \) - This indicates that 45% or more of the people following the diet will experience increased energy. - **Alternative Hypothesis (H₁):** \( p < 0.45 \) - This indicates that less than 45% of the people following the diet will experience increased energy. 2. **Collect Data:** - Sample size (n): 81 - Number of subjects experiencing increased energy (x): 42 - Sample proportion (\( \hat{p} \)): \( \frac{42}{81} \approx 0.5185 \) 3. **Calculate the Test Statistic:** - The test statistic for a proportion is calculated using the formula: \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \] where \( p_0 \) is the hypothesized population proportion (0.45). 4. **Determine the p-value:** - The p-value indicates the probability of obtaining a test statistic at least as extreme as the one observed, assuming the null hypothesis is true. This value helps us decide if we should reject the null hypothesis. 5. **Make a Decision:** - Compare the p-value with the chosen significance level (α), often set at 0.05. - If p-value < α, reject the null hypothesis. - Otherwise, do not reject the null hypothesis. 6. **Conclusion:** - State your initial conclusion based on the p-value. - Provide final conclusion: whether there is sufficient evidence to support the claim that less than 45% of the people following the diet will experience increased energy. --- By
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