A random sample of 23 adult male wolves from the Canadian Northwest Territories gave an average weight x1 = 98.6 pounds with estimated sample standard deviation s, = 7.3 pounds. Another sample of 23 adult male wolves from Alaska gave an average weight x2 = 88.2 pounds with estimated sample standard deviation s2 = 6.4 pounds. (a) Categorize the problem below according to parameter being estimated, proportion p, mean µ, difference of means u1 - H2, or difference of proportions p1 - P2. Then solve the problem. O P1 - P2 O p (b) Let µ1 represent the population mean weight of adult male wolves from the Northwest Territories, and let µ2 represent the population mean weight of adult male wolves from Alaska. Find a 90% confidence interval for 41 - H2. (Use 1 decimal place.) lower limit upper limit (c) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 90% level of confidence, does it appear that the average weight of adult male wolves from the Northwest Territories is greater than that of the Alaska wolves? Because the interval contains only positive numbers, we can say that Canadian wolves weigh more than Alaskan wolves. Because the interval contains both positive and negative numbers, we can not say that Canadian wolves weigh more than Alaskan wolves. We can not make any conclusions using this confidence interval. Because the interval contains only negative numbers, we can say that Alaskan wolves weigh more than Canadian wolves.

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.