8.52 Pull-strength tests on 10 soldered leads for a semiconductor device yield the following results, in pounds of force required to rupture the bond: 19.8 12.7 13.2 16.9 10.6 12.5 18.8 11.1 14.3 17.0 Another set of 8 leads was tested after encapsulation to determine whether the pull strength had been in- creased by encapsulation of the device, with the fol- lowing results: 24.9 22.8 23.6 22.1 20.4 21.6 21.8 22.5 Comment on the evidence available concerning equal- ity of the two population variances.
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- K Maya Paniagua - L8.5 CW.pdf X The School District of Palm Beac BA%5B"1Y9_ze2BW1NVXI00HyNvRVnRzNRvzyz6C"%5D%2C*action"%3. 8.5 HW.pdf 100% 2. BC = 28 and BD = 32 CD FD = %3D EF = F EC = IIThe vertical displacement v of a cracked slurry infiltrated fiber concrete member at maximum shear stress is given by v = a + bw, where w is the crack width, and a and b are estimated from data to be a = 2.5 ± 0.1 mm and b = 0.05 ± 0.01. Assume that w = 1.2 ± 0.1 mm.a) Estimate v, and find the uncertainty in the estimate.b) Of the uncertainties in w, a, and b, only one has a non-negligible effect on the uncertainty in v. Which one is it?The article "Effect of Microstructure and Weathering on the Strength Anisotropy of Porous Rhyolite" (Y. Matsukura, K. Hashizume, and C. Oguchi, Engineering Geology, 2002:39- 17) investigates the relationship between the angle betwween cleavage and flow structure and the strength of porous rhyolite. Strengths (in MPa) were measured for a mumber of specimens cut at various angles. The mean and standard deviation of the strengths for each angle are presented in the following table. Angle Mean 0° 22.9 Sample Size Standard Deviation 2.98 12 15° 22.9 1.16 30° 19.7 3.00 45° 14.9 2.99 60° 13.5 2.33 75° 11.9 2.10 90 14.3 3.95 6. Can you conclude that strength varies with the angle?
- In 58 specimens of a new aluminum alloy that is developed as a material for the next generation of aircraft, the compressive strength was measured, obtaining the following results: 66.4 67.7 68.0 68.0 69.5 70.4 71.6 72.9 69.0 69.169.2 69.3 69.3 69.5 70.3 71.5 72.7 68.9 69.9 70.070.0 70.1 70.2 70.3 71.3 72.6 68.8 69.8 70.8 70.971.0 71.1 71.2 71.3 72.4 68.6 69.8 70.6 71.8 71.871.9 72.1 72.2 72.3 68.4 69.7 70.6 71.7 73.3 73.574.2 74.5 75.3 68.3 69.6 70.5 71.6 73.1 a. Find a 95% confidence interval for the mean resistance of thealuminium alloy.b. If you want to test Ho:Mu =72 against H1: Mu different from 72 with a significance level of 0.05, what is the probability of a type II error for Mu= 71?Let x be per capita income in thousands of dollars. Let y be the number of medical doctors per 10,000 residents. Six small cities in Oregon gave the following information about x and y. x 8.7 9.0 9.8 8.0 8.3 8.7 y 9.8 18.2 20.6 10.2 11.4 13.1 Complete parts (a) through (e), given Σx = 52.5, Σy = 83.3, Σx2 = 461.31, Σy2 = 1257.25, Σxy = 741.13, and r ≈ 0.878. (a) Draw a scatter diagram displaying the data. Selection Tool (b) Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.) Σx = Σy = Σx2 = Σy2 = Σxy = r = (c) Find x, and y. Then find the equation of the least-squares line = a + bx. (Round your answers for x and y to two decimal places. Round your answers for a and b to three decimal places.) x = y = = + x (d) Graph the least-squares line. Be sure to plot the point (x, y) as a point on the line. (e)…The thermal conductivity (R-Value) of 23 samples of newly developed inulating material follows: 4.626 4.755 4.596 4.398 4,497 4.833 4.866 4.398 4.638 4.482 4.644 4.878 4.32 4.824 4.56 4.434 4,626 4.533 4.377 4.599 4.596 4.569 4.191 Which of the following equations should be used in to find a 95% one-sided lower Cl on the mean thermal conductivity. One answer only. X- to.05,23 X- to.05/2,23 x+ to.05/2,23 O3- tam/zz sus+ amiaa SHSX+ to.05/2,23 HsX+ to.05,23 X- to.05 SHSX+ to.05,23 None from the given choices
- 2:54 PM 65% 4 ll T-Mobile Wi-Fi ? Done 8 of 17 M ao M OF e eK O RG O a EsJ O 4 OeE C stdert deres poemtectietybildarstudentBo7est0826a0cbdogladescreariex-13 a Onteuren Cene. Caatesiny she. O Empiyt Center Ltn Saon . Uustet: i = Unit 4. Lesson 10: Estimaling Proportions from Samples Seling ssene O Ekyr in O a Tan. Pa Partae.. Next e A compary produces 1,000 blue crayons overy day. A sample of 50 crayons are analyzed, anu 3 of thern are found to not meet lne standards of the company, so they are laboled defective. A simulation is run in which 50 crayons ara chosan out of 1,0C0 so that sach crayen chosen has a 6% chance çi boing defective. The simulation is run 500 tirnes, and the mean proportion of defoctivo crayons is 0.059 vath a standard deviatlon of 0.012. 13 of 14 What is a good margin of error based on this simulation? Based on a popuation proportion estimate and margin of error, is 0.07 a plausible valle for the papuation proportion of urayors that are defoctive? Explain your…5. The compressive strength of concrete (in kg/m) is being tested b y two civil engineers. The first engineer tests ten specimens and obtains the following data: 2000 2100 2050 2150 2200 2050 2000 2100 2250 2000 While the following data is obtained by the second engineer who tests eight specimens: 2000 2200 2050 2150 2250 2100 2250 2150 The compressive strength of concrete is assumed to be normally distributed. Construct a 90% confidence interval for the ratio of standard deviation of compressive strength of all concretes.[(0.505,1.757) [ref:T2S20708] 6. A new teaching method to improve the failing rate if English SPM papers is being considered. The existing and new teaching method were applied to samples of students so as to determine whether the new teaching method improves the proportion of students who failed in their English papers. 1425 of 1500 students who were taught based on the existing teaching method and 1920 of 2000 students who were taught based on the new teaching method…An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to which polymer latex emulsións have been added during mixing) to that of unmodified mortar resulted in x = 18.11 kgf/cm2 for the modified mortar (m = 42) and y = 16.88 kgf/cm2 for the unmodified mortar (n = 31). Let ₁ and ₂ be the true average tension bond strengths for the modified and unmodified mortars, respectively. Assume that the bond strength distributions are both normal. (a) Assuming that o₁ = 1.6 and ₂ = 1.3, test Ho: ₁ - ₂ = 0 versus H₂: H₁ - H₂> 0 at level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) Z = P-value = State the conclusion in the problem context. O Fail to reject Ho. The data suggests that the difference in average tension bond strengths exceeds 0. Fail to reject Ho. The data does not suggest that the difference in average tension bond strengths…