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4.J A Maximize P = 10x + 12y subject to x + 2y < 12 3x + 2y < 24 x 2 0, y 2 0 Screen clipping taken: 11/23/2019 6:23 AM B Maximize P = 15x + 12y subject to x + y< 12 3x + y< 30 10x + 7y < 70 x 2 0, y 2 0 Screen clipping taken: 11/23/2019 6:23 AM C Maximize P = 3x + 4y + 5z subject to x + y + z< 8 3x + 2y + 4z < 24 x2 0, y > 0, z 20 Screen clipping taken: 11/23/2019 6:24 AM D Maximize P = 12x + 10y + 5z subject to 2x + y + z< 10 3x + 5y + z < 45 2x + 5y + z< 40 x2 0, y 2 0, z 2 0 Screen clipping taken: 11/23/2019 6:25 AM

4.J A Maximize P = 10x + 12y subject to x + 2y < 12 3x + 2y < 24 x 2 0, y 2 0 Screen clipping taken: 11/23/2019 6:23 AM B Maximize P = 15x + 12y subject to x + y< 12 3x + y< 30 10x + 7y < 70 x 2 0, y 2 0 Screen clipping taken: 11/23/2019 6:23 AM C Maximize P = 3x + 4y + 5z subject to x + y + z< 8 3x + 2y + 4z < 24 x2 0, y > 0, z 20 Screen clipping taken: 11/23/2019 6:24 AM D Maximize P = 12x + 10y + 5z subject to 2x + y + z< 10 3x + 5y + z < 45 2x + 5y + z< 40 x2 0, y 2 0, z 2 0 Screen clipping taken: 11/23/2019 6:25 AM

Practical Management Science
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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A O Standord Max Мaximize Р — 10х + 12y subject to x + 2y < 12 max do frenct 3x + 2y < 24 daj • varidoles nonnegaitive E inequalities x2 0, y 2 0 Screen clipping taken: 11/23/2019 6:23 AM В Maximize P = 15x + 12y subject to x + y<12 3x + y< 30 10x + 7y < 70 x2 0, y > 0 Screen clipping taken: 11/23/2019 6:23 AM C Мaximize P 3 3х + 4у + 5z subject to x + y + z < 8 3x + 2y + 4z < 24 x2 0, y > 0, z 20 Screen clipping taken: 11/23/2019 6:24 AM D Maximize P = 12x + 10y + 5z subject to 2х + у +zs 10 3x + 5y + z < 45 2x + 5y + z < 40 x 2 0, y 2 0, z 2 0 Screen clipping taken: 11/23/2019 6:25 AM
Transcribed Image Text:A O Standord Max Мaximize Р — 10х + 12y subject to x + 2y < 12 max do frenct 3x + 2y < 24 daj • varidoles nonnegaitive E inequalities x2 0, y 2 0 Screen clipping taken: 11/23/2019 6:23 AM В Maximize P = 15x + 12y subject to x + y<12 3x + y< 30 10x + 7y < 70 x2 0, y > 0 Screen clipping taken: 11/23/2019 6:23 AM C Мaximize P 3 3х + 4у + 5z subject to x + y + z < 8 3x + 2y + 4z < 24 x2 0, y > 0, z 20 Screen clipping taken: 11/23/2019 6:24 AM D Maximize P = 12x + 10y + 5z subject to 2х + у +zs 10 3x + 5y + z < 45 2x + 5y + z < 40 x 2 0, y 2 0, z 2 0 Screen clipping taken: 11/23/2019 6:25 AM
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