Please answer all parts 4. The figure below shows a countershaft with helical gear (B), bevel gear (D), and two supportingbearings (A and C). All shoulder fillets (at points where diameter changes) have a radius of 5 mm.Note that the shaft is designed so that only bearing A takes thrust (There is a resultant force in thex-direction).F= 0.3675Fy Fx =0.2625Fy(1)Forces act at 500-mm dia.сB550-400-D= 1.37 kN400450F = 5.33 KN120 dia.Keyway80 dia.F = 1.37 kN(K 1.6 for bend and torsion; 1.0 for axialload all at the keyway. Use Cs = 1 with these values.)Forces act at 375-mm dia.(2)The shaft is made of hardened steel, with ultimate strength = 1069 MPa and yield strength =MPa. All surfaces are finished by grinding, and a 99% reliability is desired.a) Find F on the 500 mm diameter bearing. (Hint: Use equilibrium of torques)F,yb) Draw VMNT diagrams for the shaft in the xy and xz planes.c) At point B, calculate the equivalent stresses.0d) Estimate the safety factor for infinite life ifea= constantσem$896

Answered: Image /qna-images/answer/ee15633f-c9c8-4faa-99bc-2c4233f7ebcf.jpg

Answered: 4. The figure below shows a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A pinion having 40 teeth drives a gear having 80 teeth. the profile of the gear is involute with pressure angle ( 22), 12 mm module and (14) mm addendum. Find 1-the length of contact2-Arc of contact 3-Contact ratio
A gear train with a ratio of -6:1 and a diametral pitch of 8 is used to reduce the speed from an electric motor to a shaft driving a grocery checkout conveyor. Grocery checkout conveyor Electric motor @, = 1800 rpm a. If the motor rotates at 1800 rpm clockwise, determine the speed and direction of the large gear. b. For a pressure angle of 20 deg, determine the minimum number of teeth for the pinion. Assume the gears are cut by a shaper (NOT a hob). c. Specify pitch diameters and numbers of teeth for the pinion and the gear for the most compact gear train.
In the figure below is a proposed shaft design. The shaft is designed with a motor attached to the overhang (right side) with a flexible coupling. The motor provides a torque of 2500 lbf·in at a speed of 1200 rpm. A spur gear with a 20° pressure angle and a pitch diameter of 4 in is located at the key seat in between the two bearings and supposed to transmit the power out. A ball bearing and cylindrical bearing are planned for the left and right support respectively. Determine the minimum fatigue factor of safety by evaluating at any critical locations. Use the DE-ASME Elliptic fatigue criterion. Compute the deformation using an approximated shaft of 1.875 in uniform diameter and determine if it has adequate rigidity by comparing against the number given in Table 7-2.
Photo by Norbert Schnitzler, CC BY-SA 2.0 simple model 36 in bearing bearing fixed support A simplified model of two solid circular shafts connected by two rigid gears is given below. Determine: (1) the torque in shaft c-d to the nearest in-lb and (2) the angle of twist at point a in degrees with two decimal places. b bearing bearing a 62 in Notes: top view (sketch not to scale) - gear b radius= 1.25 in - gear c radius = 4.60 in - shaft ab radius = 1.00 in -shaft cd radius = 0.75 in - shear modulus = 12000 ksi 1100 in-lb
Ex. #5] Pinion 2 in the figure runs at 1 750 rpm and transmits 2.5 kW to idler gear 3. The teeth are cut on the 20° full-depth system and have a module of m= 2.5 mm. Draw the free body diagram of gear 3 and shows all the forces acting upon it. Determine the forces acting upon gear 3. The direction of rotation of gear 3, as shown, is counterclockwise. GIVEN: Figure shown N₂ = 1750 rpm $=200 P = 2.5 kW m = 2.5 mm 3 0₂ REQUIRED: CS Draw the freechody distram of gear 3 and compute the forces acting on it.
The figure shows a pair of shaft-mounted spur gears having a diametral pitch of 5 teeth/in with an 18-tooth 20° pinion driving a 45-tooth gear. The power input is 28-hp at 1700 rev/min. Find the magnitude of the force acting on bearing D. 3 2 3 in 3 in The magnitude of the force acting on bearing Dis lbf.
a) A line shaft as shown in Figure Q is driven using a motor placed vertically below it. The pulley on the line shaft is 1.6 m in diameter and has belt tensions 7.5 kN and 2.4 kN on the tight side and slack side of the belt respectively. Both tensions may be assumed to be vertical and the weight of the pulley is negligible. If the pulley is overhang from the shaft, the distance of the centre line of the pulley from the centre line of the bearing being 500 mm.6.Figure Q(i) Predict using distortion energy theory, the appropriate diameter of the shaft that failure will not occur if the yield strength, Sy = 370 Mpa and factor of safety is 2.5. (ii) Assuming the maximum allowable shear stress of 42 MPa, find its diameter using maximum shear stress theory. (iii) Comparing the diameters in (i) and (iii) above, which of them would you have used to design your shaft and why?
The diameters of the solid shafts in the gear wheel set shown in the figure are dAB = 20mm, dCD = 25mm, dEF = 40mm. Since the safety shear stress of each shaft is 90MPa, determine the largest T torque that can be applied. Calculate the total angle of rotation in A for the maximum applied torque value.
Please prove the answer to this exercise, the answer is already given, written in bold. Thank you
Solve part b,c and d only
The four helical gears shown in figure have a module in the normal plane of 4 mm and a pressure angle in the normal plane of 0.35 rad. The motor shaft rotates 550 rpm and transmits 20 kW. Other data are on the drawing. (a) What is the speed ratio between the motor (input) and output shafts? (b) Determine all force components that the 20-tooth pinion applies to the 50-tooth gear. Make a sketch showing these forces applied to the gear. (c) The same as part (b), except for the force components that the 50-tooth gear exerts on the 25- tooth pinion 100 50 teeth 200 125 25 teeth ψ = 0.35 rad right hand Motor 20 teeth ψ = 0.50 rad left hand 50 teeth Output

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