4. Here’s a figure-it-out mechanism, resulting in the formation of p-aminophenol from anaromatic hydroxylamine. Would you expect either ortho- or meta-aminophenol to form incompetition? Why or why not?HH;0*H-NНОH2OОНH5. (a) The triaryl hydroxylamine hydrolyzes in acid to form two products: one compoundcontaining two aromatic rings and one with a single aromatic ring. First, draw the two productsand the mechanism of their formation in acidic water (this is another "figure it out" mechanism).PhH;O*Ph—С—NH,0PhОН(b) Suppose one of the aryl rings had a t-donating group (-OCH3) and the other had a n-withdrawing group (-NO2), both in the para position. Where would the substituents end up in theproducts (draw them)? Why? Do you suspect this reaction is under kinetic control orthermodynamic control, or both/either?

Introduction: The formation of para-aminophenol takes place through N-phenyl hydroxylamine. The…

4. Here's a figure-it-out mechanism, resulting in the formation of p-aminophenol from an aromatic hydroxylamine. Would you expect either ortho- or meta-aminophenol to form in competition? Why or why not? H. H;0* HO H20 ОН H.

4. Here's a figure-it-out mechanism, resulting in the formation of p-aminophenol from an aromatic hydroxylamine. Would you expect either ortho- or meta-aminophenol to form in competition? Why or why not? H. H;0* HO H20 ОН H.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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