4. Calculate At for the reaction, NHI) + 02(g) - N2(g) + 2H0(I), from the following data: 2NH.(g) = 3N20(g) - 4N2(g) + 3H20 (I) ДН = - 1010 KJ N20(g) = 3H(g) -> NzH4(1) + H,0(I) AH = -317 KJ 2NHs(g0 + 1/202(g) - AH = - 143 KJ H2(g) + 1/202(g) > H2O(I) AH = -286 KJ

4. Calculate At for the reaction, NHI) + 02(g) - N2(g) + 2H0(I), from the following data: 2NH.(g) = 3N20(g) - 4N2(g) + 3H20 (I) ДН = - 1010 KJ N20(g) = 3H(g) -> NzH4(1) + H,0(I) AH = -317 KJ 2NHs(g0 + 1/202(g) - AH = - 143 KJ H2(g) + 1/202(g) > H2O(I) AH = -286 KJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter17: Spontaneity, Entropy, And Free Energy

Section: Chapter Questions

Problem 1ALQ: For the process A(l) A(g), which direction is favored by changes in energy probability? Positional...

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