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4. A circuit has three AC sources: y₁ = 5cos(wt + 30°), y2 = 4cos(wt + 120°), y3 2cos(wt 60°), calculating: = (1) y₁ + y2 y3, and express the addition in the complex plane using phasors. (2) y1 y2 y3, and express the subtraction in the complex plane using phasors

4. A circuit has three AC sources: y₁ = 5cos(wt + 30°), y2 = 4cos(wt + 120°), y3 2cos(wt 60°), calculating: = (1) y₁ + y2 y3, and express the addition in the complex plane using phasors. (2) y1 y2 y3, and express the subtraction in the complex plane using phasors

Power System Analysis and Design (MindTap Course List)
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.6P: (a) Transform v(t)=75cos(377t15) to phasor form. Comment on whether =377 appears in your answer. (b)...
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4. A circuit has three AC sources: y₁ = 5cos(wt + 30°), y2 = 4cos(wt + 120°), y3 2cos(wt 60°), calculating: = (1) y₁ + y2 y3, and express the addition in the complex plane using phasors. (2) y1 y2 y3, and express the subtraction in the complex plane using phasors
Transcribed Image Text:4. A circuit has three AC sources: y₁ = 5cos(wt + 30°), y2 = 4cos(wt + 120°), y3 2cos(wt 60°), calculating: = (1) y₁ + y2 y3, and express the addition in the complex plane using phasors. (2) y1 y2 y3, and express the subtraction in the complex plane using phasors
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