4) A Column foundation as can be seen in the bottom, is 3mx2m in plane with Dr = 2 m, ø' = 25, c' = 50 kN/m2. Considering FS = 4 determine the net allowable load. The foundation could carry. (Use general equation) y= 16.8 kN/m³ : 1 m 2 m Groundwater level 3 m x 2 m Ysar = 19.4 kN/m³

4) A Column foundation as can be seen in the bottom, is 3mx2m in plane with Dr = 2 m, ø' = 25, c' = 50 kN/m2. Considering FS = 4 determine the net allowable load. The foundation could carry. (Use general equation) y= 16.8 kN/m³ : 1 m 2 m Groundwater level 3 m x 2 m Ysar = 19.4 kN/m³

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

A column foundation as can be seen in the bottom, is 3mx2min plane with Df = 2 m, ø' = 25, c’ = 50 kN/m2. Considering FS = 4 determine the net allowable load. The foundation could carry. (Use general equation)

4) A Column foundation as can be seen in the bottom, is 3mx2m in plane with Dr =
2 m, ø' = 25, c' = 50 kN/m?. Considering FS = 4 determine the net allowable load.
The foundation could carry. (Use general equation)
y= 16.8 kN/m³ :
1 m
2 m
Groundwater level
3 m x 2 m
Ysar = 19.4 kN/m³

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Q1: A column foundation (Fig. 1) is 3 mx 2 m in plan. Given: 25%, C-50 kN/m². Using modified Meyerhof's equation and FS-4, determine the net allowable load the Dr-2m. foundation could carry. H 3mx2m 7-168 AN leval
Use Terzaghi's equation and Terzaghi's Table
pls ans quickly dear eng
The total load on a shallow foundation is 400 kN and the safe bearing capacity of the soilis 200 kN/m2. The area of the footing required, is.
Problem 6: A 1.5m square foundation was constructed at a depth of lm. The y =19.0 kN/m², c' = 10 kN/m² and o' = 24° deg and a FOS of 3.0. Find the maximum column load that can be applied.
2. The column load of a square foundation (Figure 1) is given. If the depth of foundation D= 4 ft, 0=30°, and c = 0. Using Terzaghi's bearing capacity equation and FS = 2.5, determine the proper size of the footing. D.L. = 80 kip L.L. = 60 kip qult = 1.3 c N. + qN, + 0.4 y B N, Figure 1 TABLE 2.1 Terzaghi's Bearing Capacity Factors-Eqs. (2.32), (2.33), and (2.34) N. N, N. N. N, N. N, N, Ysoil = 118 pcf 2 ft W.T 1.00 0.00 17 14.60 0.01 18 15.12 1.22 0.04 19 | 16.57 6.62 1.35 0.06 20 | 17.69 1.49 0.10 21 | 18.92 |1.64 0.14 22 20.27 1.81 0.20 23 21.75 2.00 0.27 24 23.36 2.21 0.35 25 25.13 2.44 0.44 26 27.09 9.61 2.69 0.56 27 29.24 5.70 5.45 2.18 34 2.59 35 36 52.64 57.75 36.50 38.04 D; = 4m 6.00 1.1 6.04 41.44 45.41 6.30 6.70 3.07 63.53 47.16 54.36 3.64 4.31 38 5.09 39 70.01 77.50 85.97 95.66 106.81 65.27 78.61 95.03 3 7.44 37 53.80 8.26 9.19 61.55 70.61 4 6.97 5 7.34 3m x2m 6. 7.73 10.23 6.00 40 81.27 115.31 11.40 12.72| 8.34 8.15 7.08 41 93.85 140.51 171.99 211.56 8 8.60 42 119.67…