For a square foundation, according to the information given and the assumption of vertical load, it is desirable to determine the dimensions of the foundation. Use the general formula. D, = 2 m; Qa = 3330 kN, y = 16.5 kN/m'; 6' = 30°; c' = 0; and FS = 4.

For a square foundation, according to the information given and the assumption of vertical load, it is desirable to determine the dimensions of the foundation. Use the general formula. D, = 2 m; Qa = 3330 kN, y = 16.5 kN/m'; 6' = 30°; c' = 0; and FS = 4.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

For a square foundation, according to the information given and the assumption
of vertical load, it is desirable to determine the dimensions of the foundation.
Use the general formula.
D, = 2 m; Qa = 3330 kN, y = 16.5 kN/m'; 6' = 30°; c' = 0; and FS 4.

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2. The column load of a square foundation (Figure 1) is given. If the depth of foundation D= 4 ft, 0=30°, and c = 0. Using Terzaghi's bearing capacity equation and FS = 2.5, determine the proper size of the footing. D.L. = 80 kip L.L. = 60 kip qult = 1.3 c N. + qN, + 0.4 y B N, Figure 1 TABLE 2.1 Terzaghi's Bearing Capacity Factors-Eqs. (2.32), (2.33), and (2.34) N. N, N. N. N, N. N, N, Ysoil = 118 pcf 2 ft W.T 1.00 0.00 17 14.60 0.01 18 15.12 1.22 0.04 19 | 16.57 6.62 1.35 0.06 20 | 17.69 1.49 0.10 21 | 18.92 |1.64 0.14 22 20.27 1.81 0.20 23 21.75 2.00 0.27 24 23.36 2.21 0.35 25 25.13 2.44 0.44 26 27.09 9.61 2.69 0.56 27 29.24 5.70 5.45 2.18 34 2.59 35 36 52.64 57.75 36.50 38.04 D; = 4m 6.00 1.1 6.04 41.44 45.41 6.30 6.70 3.07 63.53 47.16 54.36 3.64 4.31 38 5.09 39 70.01 77.50 85.97 95.66 106.81 65.27 78.61 95.03 3 7.44 37 53.80 8.26 9.19 61.55 70.61 4 6.97 5 7.34 3m x2m 6. 7.73 10.23 6.00 40 81.27 115.31 11.40 12.72| 8.34 8.15 7.08 41 93.85 140.51 171.99 211.56 8 8.60 42 119.67…