3A+4B→2C is found to be second order with respect to A and the rate constant for the reaction is k = 2.98* 10^ {-9}k=2.98∗10^−9 \frac{L}{mole\cdot\sec}mole⋅secL​. If the initial concentration of A is 0.89 M0.89M how much many seconds will be required for the concentration of A to reach 0.65 M0.65M   you can input your answer as a whole number

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