This is based on the binding of glucose to hexokinase.  The enzyme concentrations are constantly (a) 1.34 mmol dm–3, (b) 3.00 mmol dm–3, and (c) 10.0 mmol dm–3. Find the orders of reaction with respect to glucose and hexokinase and the rate constant. How any seconds will it take to consume 75% glucose by moles if [glucose]0 = 5.00 mmol dm–3, assuming the volume of reaction mixture is constant

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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This is based on the binding of glucose to hexokinase. 

The enzyme concentrations are constantly (a) 1.34 mmol dm–3, (b) 3.00 mmol dm–3, and (c) 10.0 mmol dm–3. Find the orders of reaction with respect to glucose and hexokinase and the rate constant. How any seconds will it take to consume 75% glucose by moles if [glucose]0 = 5.00 mmol dm–3, assuming the volume of reaction mixture is constant. 

[glucose],/(mmol
1.00
1.54
3.12
4.02
dm-3)
(a)
(b)
(c)
5.0
7.6
15.5
20.0
Vo/(mol dm-3 s-1)
7.0
11.0
23.0
31.0
21.0
34.0
70.0
96.0
Transcribed Image Text:[glucose],/(mmol 1.00 1.54 3.12 4.02 dm-3) (a) (b) (c) 5.0 7.6 15.5 20.0 Vo/(mol dm-3 s-1) 7.0 11.0 23.0 31.0 21.0 34.0 70.0 96.0
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