The enzyme carbonic anhydrase catalyzes the following reaction: CO2 (g) + H2O(1) + HCO3-(aq) + H+ (aq) -1 In water, without the enzyme, the reaction proceeds with a rate constant of 0.039 s at 24 °C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of 1.0 ×106 s-1 at 24 °C. Part A Assuming the collision factor is the same for both situations, calculate the difference in activation energies for the uncatalyzed (Ea) versus the enzyme-catalyzed (Eac) reaction. Express your answer in kilojoules to two significant figures. Ea – Eac = kJ Submit Request Answer
The enzyme carbonic anhydrase catalyzes the following reaction: CO2 (g) + H2O(1) + HCO3-(aq) + H+ (aq) -1 In water, without the enzyme, the reaction proceeds with a rate constant of 0.039 s at 24 °C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of 1.0 ×106 s-1 at 24 °C. Part A Assuming the collision factor is the same for both situations, calculate the difference in activation energies for the uncatalyzed (Ea) versus the enzyme-catalyzed (Eac) reaction. Express your answer in kilojoules to two significant figures. Ea – Eac = kJ Submit Request Answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The enzyme carbonic anhydrase catalyzes the following reaction:
\[ \text{CO}_2(g) + \text{H}_2\text{O}(l) \rightarrow \text{HCO}_3^-(aq) + \text{H}^+(aq) \]
In water, without the enzyme, the reaction proceeds with a rate constant of 0.039 s\(^{-1}\) at 24°C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of \(1.0 \times 10^6\) s\(^{-1}\) at 24°C.
**Part A**
Assuming the collision factor is the same for both situations, calculate the difference in activation energies for the uncatalyzed (\(E_a\)) versus the enzyme-catalyzed (\(E_{ac}\)) reaction.
Express your answer in kilojoules to two significant figures.
\[ E_a - E_{ac} = \] kJ
[Submit] [Request Answer]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7fcffe20-88c0-46a7-a9a5-147a481f673b%2F5fdf6e57-4837-4223-9986-3eabf1c28cc8%2F92407vk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The enzyme carbonic anhydrase catalyzes the following reaction:
\[ \text{CO}_2(g) + \text{H}_2\text{O}(l) \rightarrow \text{HCO}_3^-(aq) + \text{H}^+(aq) \]
In water, without the enzyme, the reaction proceeds with a rate constant of 0.039 s\(^{-1}\) at 24°C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of \(1.0 \times 10^6\) s\(^{-1}\) at 24°C.
**Part A**
Assuming the collision factor is the same for both situations, calculate the difference in activation energies for the uncatalyzed (\(E_a\)) versus the enzyme-catalyzed (\(E_{ac}\)) reaction.
Express your answer in kilojoules to two significant figures.
\[ E_a - E_{ac} = \] kJ
[Submit] [Request Answer]
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