The enzyme carbonic anhydrase catalyzes the following reaction: CO2 (g) + H2O(1) + HCO3-(aq) + H+ (aq) -1 In water, without the enzyme, the reaction proceeds with a rate constant of 0.039 s at 24 °C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of 1.0 ×106 s-1 at 24 °C. Part A Assuming the collision factor is the same for both situations, calculate the difference in activation energies for the uncatalyzed (Ea) versus the enzyme-catalyzed (Eac) reaction. Express your answer in kilojoules to two significant figures. Ea – Eac = kJ Submit Request Answer

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Chapter1: Chemical Foundations
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The enzyme carbonic anhydrase catalyzes the following reaction:

\[ \text{CO}_2(g) + \text{H}_2\text{O}(l) \rightarrow \text{HCO}_3^-(aq) + \text{H}^+(aq) \]

In water, without the enzyme, the reaction proceeds with a rate constant of 0.039 s\(^{-1}\) at 24°C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of \(1.0 \times 10^6\) s\(^{-1}\) at 24°C.

**Part A**

Assuming the collision factor is the same for both situations, calculate the difference in activation energies for the uncatalyzed (\(E_a\)) versus the enzyme-catalyzed (\(E_{ac}\)) reaction.

Express your answer in kilojoules to two significant figures.

\[ E_a - E_{ac} = \] kJ

[Submit] [Request Answer]
Transcribed Image Text:The enzyme carbonic anhydrase catalyzes the following reaction: \[ \text{CO}_2(g) + \text{H}_2\text{O}(l) \rightarrow \text{HCO}_3^-(aq) + \text{H}^+(aq) \] In water, without the enzyme, the reaction proceeds with a rate constant of 0.039 s\(^{-1}\) at 24°C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of \(1.0 \times 10^6\) s\(^{-1}\) at 24°C. **Part A** Assuming the collision factor is the same for both situations, calculate the difference in activation energies for the uncatalyzed (\(E_a\)) versus the enzyme-catalyzed (\(E_{ac}\)) reaction. Express your answer in kilojoules to two significant figures. \[ E_a - E_{ac} = \] kJ [Submit] [Request Answer]
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