The activation energy for the gas phase isomerization of methyl cis-cinnamate is 174 kJ. cis-C6H5 CH=CHCOOCH3 → trans-C6H5 CH=CHCOOCH3 The rate constant at 652 K is 4.09 x 10-4 s¹. The rate constant will be 0.00285 s¹ at S K.

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Chapter1: Chemical Foundations
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**Chemical Reaction and Kinetics**

The activation energy for the gas phase isomerization of methyl cis-cinnamate is 174 kJ.

**Chemical Equation:**
\[ \text{cis-C}_6\text{H}_5 \text{CH} = \text{CHCOOCH}_3 \rightarrow \text{trans-C}_6\text{H}_5 \text{CH} = \text{CHCOOCH}_3 \]

**Rate Constants:**
- The rate constant at 652 K is \( 4.09 \times 10^{-4} \, \text{s}^{-1} \).
- The rate constant will be \( 0.00285 \, \text{s}^{-1} \) at [blank] K.

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Transcribed Image Text:**Chemical Reaction and Kinetics** The activation energy for the gas phase isomerization of methyl cis-cinnamate is 174 kJ. **Chemical Equation:** \[ \text{cis-C}_6\text{H}_5 \text{CH} = \text{CHCOOCH}_3 \rightarrow \text{trans-C}_6\text{H}_5 \text{CH} = \text{CHCOOCH}_3 \] **Rate Constants:** - The rate constant at 652 K is \( 4.09 \times 10^{-4} \, \text{s}^{-1} \). - The rate constant will be \( 0.00285 \, \text{s}^{-1} \) at [blank] K. **Interactive Options:** - **Submit Answer**: Click to submit your solution. - **Retry Entire Group**: Option to retry the problem set. - **Attempts Indicator**: Indicates 9 more group attempts remaining.
The gas phase decomposition of nitrogen dioxide at 383 °C

\[ \text{NO}_2 (g) \rightarrow \text{NO}(g) + \frac{1}{2} \text{O}_2 (g) \]

is second order in \(\text{NO}_2\).

In one experiment, when the initial concentration of \(\text{NO}_2\) was 0.136 M, the concentration of \(\text{NO}_2\) dropped to \(3.62 \times 10^{-2}\) M after 28.7 seconds had passed.

Based on these data, the rate constant for the reaction is \(\boxed{\,}\) M\(^{-1}\) s\(^{-1}\).
Transcribed Image Text:The gas phase decomposition of nitrogen dioxide at 383 °C \[ \text{NO}_2 (g) \rightarrow \text{NO}(g) + \frac{1}{2} \text{O}_2 (g) \] is second order in \(\text{NO}_2\). In one experiment, when the initial concentration of \(\text{NO}_2\) was 0.136 M, the concentration of \(\text{NO}_2\) dropped to \(3.62 \times 10^{-2}\) M after 28.7 seconds had passed. Based on these data, the rate constant for the reaction is \(\boxed{\,}\) M\(^{-1}\) s\(^{-1}\).
Expert Solution
Step 1: Arrhenius equation

Note: As per the guidelines, solution of 1st question has been made. For the expert solution of 2nd question kindly post it separately.

Answer-1

ln straight k subscript 2 over straight k subscript 1 equals straight E subscript straight a over straight R open parentheses 1 over straight T subscript 1 minus 1 over straight T subscript 2 close parentheses

Here:

straight E subscript straight a equals Activation space energy
straight R equals Universal space gas space constant

k1 and k2 are rate constants at temperatures T1 and T2 respectively

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