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The first-order rate constant for the decomposition of CH3N₂CH3, CH3N₂CH3(g) → C₂H5(9) + N₂(g) at 327 °C is k = 3.60e- 04 s ¹. Suppose we start with 0.0858 mol of CH3N₂CH3 in a volume of 6.9 L. How many moles of CH3N₂CH3 will remain after 3.79e+01 min? a) 0.0846 moles will remain. b) 0.00117 moles will remain. c) 6.81e-79 moles will remain. d) 0.0703 moles will remain. e) 0.0378 moles will remain.

The first-order rate constant for the decomposition of CH3N₂CH3, CH3N₂CH3(g) → C₂H5(9) + N₂(g) at 327 °C is k = 3.60e- 04 s ¹. Suppose we start with 0.0858 mol of CH3N₂CH3 in a volume of 6.9 L. How many moles of CH3N₂CH3 will remain after 3.79e+01 min? a) 0.0846 moles will remain. b) 0.00117 moles will remain. c) 6.81e-79 moles will remain. d) 0.0703 moles will remain. e) 0.0378 moles will remain.

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 60E: The rate constant for the decomposition of acetaldehyde, CH3CHO, t0 methane, CH4, and carbon...
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The first-order rate constant for the decomposition of CH3N₂CH3, CH3N₂CH3(g) → C₂H5(9) + N₂(g) at 327 °C is k = 3.60e- 04 s ¹. Suppose we start with 0.0858 mol of CH3N₂CH3 in a volume of 6.9 L. How many moles of CH3N₂CH3 will remain after 3.79e+01 min? a) 0.0846 moles will remain. b) 0.00117 moles will remain. c) 6.81e-79 moles will remain. d) 0.0703 moles will remain. e) 0.0378 moles will remain.
Transcribed Image Text:The first-order rate constant for the decomposition of CH3N₂CH3, CH3N₂CH3(g) → C₂H5(9) + N₂(g) at 327 °C is k = 3.60e- 04 s ¹. Suppose we start with 0.0858 mol of CH3N₂CH3 in a volume of 6.9 L. How many moles of CH3N₂CH3 will remain after 3.79e+01 min? a) 0.0846 moles will remain. b) 0.00117 moles will remain. c) 6.81e-79 moles will remain. d) 0.0703 moles will remain. e) 0.0378 moles will remain.
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