The first-order rate constant for the decomposition of N2O5, 2N2O5 (g)→4NO2(g) + O2 (g) at 70°C is 6.82 × 10¬³ s-1. Suppose we start with 2.60x10-2 mol of N2O5 (g) in a volume of 2.5 L .

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How many moles of N2O5 will remain after 4.0 min ?
Express the amount in moles to two significant digits.
The first-order rate constant for the decomposition of \( \text{N}_2\text{O}_5 \),

\[ 2\text{N}_2\text{O}_5(g) \rightarrow 4\text{NO}_2(g) + \text{O}_2(g) \]

at 70°C is \( 6.82 \times 10^{-3} \, \text{s}^{-1} \). Suppose we start with \( 2.60 \times 10^{-2} \, \text{mol} \) of \( \text{N}_2\text{O}_5(g) \) in a volume of 2.5 L.
Transcribed Image Text:The first-order rate constant for the decomposition of \( \text{N}_2\text{O}_5 \), \[ 2\text{N}_2\text{O}_5(g) \rightarrow 4\text{NO}_2(g) + \text{O}_2(g) \] at 70°C is \( 6.82 \times 10^{-3} \, \text{s}^{-1} \). Suppose we start with \( 2.60 \times 10^{-2} \, \text{mol} \) of \( \text{N}_2\text{O}_5(g) \) in a volume of 2.5 L.
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