30. The expression for the equilibrium constant for the following reaction. 2H,S) =2H) +Se) is 2(x) 2(8) [H,F[s.] [H,sF If [H,S]= 4.84x10 moldm, Ke = [H,]=1.50x10 moldm and the equilibrium constant for the reaction is 2.25 x 104. Calculate the [S2] at equilibrium. A 2.25 x 103 в 3.5х 103 3.5 x C 4.84 x 10 D 2.34 x 10 В C
30. The expression for the equilibrium constant for the following reaction. 2H,S) =2H) +Se) is 2(x) 2(8) [H,F[s.] [H,sF If [H,S]= 4.84x10 moldm, Ke = [H,]=1.50x10 moldm and the equilibrium constant for the reaction is 2.25 x 104. Calculate the [S2] at equilibrium. A 2.25 x 103 в 3.5х 103 3.5 x C 4.84 x 10 D 2.34 x 10 В C
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![30.
The expression for the equilibrium constant
for the following reaction.
2H,S) = 2H26) + Se)
is
2(x)
Ke = HF[s,]
[H,sF
If [H,S]= 4.84x10* moldm,
[H,]=1.50x10 moldm and the
equilibrium constant for the reaction is
2.25 x 104. Calculate the [S2] at equilibrium.
A 2.25 x 103
3.5 x 103
4.84 x 10
D 2.34 x 103
B
C
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a6d9c67-6f13-49d2-ac4d-2d996f90a88b%2Feab2d19b-0d4b-406a-a057-a9f3e902518d%2Fn66rwzf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:30.
The expression for the equilibrium constant
for the following reaction.
2H,S) = 2H26) + Se)
is
2(x)
Ke = HF[s,]
[H,sF
If [H,S]= 4.84x10* moldm,
[H,]=1.50x10 moldm and the
equilibrium constant for the reaction is
2.25 x 104. Calculate the [S2] at equilibrium.
A 2.25 x 103
3.5 x 103
4.84 x 10
D 2.34 x 103
B
C
D
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