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Text Box: 0.2 g of a volatile liquid on complete evaporation occupied a volume of 30 cm3 at standard temperature and pressure (0 °C, 1 atm). The relative molecular mass of the liquid can be calculated from the expression 2240 X 0.20 A. 30 24000 X 0.20 В. 20 22400 C. 0.20 X 30 30 D. 0.20 X 23400

Text Box: 0.2 g of a volatile liquid on complete evaporation occupied a volume of 30 cm3 at standard temperature and pressure (0 °C, 1 atm). The relative molecular mass of the liquid can be calculated from the expression 2240 X 0.20 A. 30 24000 X 0.20 В. 20 22400 C. 0.20 X 30 30 D. 0.20 X 23400

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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11. Text Box: 0.2 g of a volatile liquid on complete evaporation occupied a volume of 30 cm3 at standard temperature and pressure (0 °C, 1 atm). The relative molecular mass of the liquid can be calculated from the expression 2240 X 0.20 А. 30 24000 X 0.20 В. 20 22400 С. 0.20 X 30 30 D. 0.20 X 23400
Transcribed Image Text:11. Text Box: 0.2 g of a volatile liquid on complete evaporation occupied a volume of 30 cm3 at standard temperature and pressure (0 °C, 1 atm). The relative molecular mass of the liquid can be calculated from the expression 2240 X 0.20 А. 30 24000 X 0.20 В. 20 22400 С. 0.20 X 30 30 D. 0.20 X 23400
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