3. A dynamic system with the following feedback architecture will be controlled byselecting appropriate positive values for amplifier gain Ka and sensor gain KCis)K.2+1KHint: The block diagram of inner loop is reduced asR(sC(s)Ka2s2+(KaKn+1)sa) What will be the steady state error of the closed loop system to unit impulse input?b)Determine natural frequency, damping ratio, the gains Ka and Ka that will make theclosed loop system have the following unit step response.Step Response1.4Time (seconds) 181Amplitude. 1.161.2Time (seconds) 121Ampitude: 1Time (seconds): 4.0.8Ampitude 0.980.6040.24.6.Time (seconds)Amplitude

The forward path gain and feedback gain of a negative feedback closed system are Gs=Ka2s2+KaKh+1s,…

3. A dynamic system with the following feedback architecture will be controlled by selecting appropriate positive values for amplifier gain K. and sensor gain K. R Es) Cin K 2+1 K Hint: The block diagram of inner loop is reduced as R(s C(s) Ка 2s2+(KaKn+1)s a) What will be the steady state error of the closed loop system to unit impulse input? h)Determine natural frequency, damping ratio, the gains Ka and Kx that will make the closed loop system have the following unit step response. Step Response 1.4 Time (seconds) 181 Amplitude. 1.16 1.2 Time (seconds): 121 Ampitude: 1 Time (seconds): 4. 0.8 Armpitude 0.98 0.6 0.4 0.2 1. 3 4. 6. Time (seconds) Amplitude

3. A dynamic system with the following feedback architecture will be controlled by selecting appropriate positive values for amplifier gain K. and sensor gain K. R Es) Cin K 2+1 K Hint: The block diagram of inner loop is reduced as R(s C(s) Ка 2s2+(KaKn+1)s a) What will be the steady state error of the closed loop system to unit impulse input? h)Determine natural frequency, damping ratio, the gains Ka and Kx that will make the closed loop system have the following unit step response. Step Response 1.4 Time (seconds) 181 Amplitude. 1.16 1.2 Time (seconds): 121 Ampitude: 1 Time (seconds): 4. 0.8 Armpitude 0.98 0.6 0.4 0.2 1. 3 4. 6. Time (seconds) Amplitude

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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The margins of stability for K = 12 of the unit feedback system shown in the figure are given below. Phase crossover frequency : Wfc = 2rad/s Gain crossover frequency: wgc = 1.4rad/s Phase Margin = 16.8 degree Amplitude Margin Kg = 6dB (NOTE: Use 3 decimal places in your operations.) a) Calculate the amplitude margin for K 60. b) Calculate the point where the KG(jw) Nyquist Diagram intersects the negative real axis for K 60.
2) The amplifier circuit shown below has the following parameters: Rid = 200k, ro = 2k2, an open loop gain = μ = 106. If the factor 1+Aßf) = 15. a) State the type of feedback topology circuit. b) Identify the feedback portion of the circuit. c) Determine R₁1 and R22. d) Draw the small AC equivalent circuit of the below amplifier. e) Determine Aƒ. f) Determine Rif and Rof. Is S RS www +1₁ 100 R1 •MW". 3k OPAMP R2 ww 1k R3 R4 www 4k 3k Vo
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(2) ukäi Q) In the negative feedback, which of the following * .statement is true (a) Gain, noise, distortion as well as the bandwidth of the amplifier are decreases. (b) The feedback is out of phase with their input signal and the the gain stability decreases. (c) It is called regenerative and used in amplifiers. (d) The input voltage is reduced and the input and output impedances are improved.
Q.4. Consider a unity feedback control system with feed forward :transfer function is .Q.4 G(s) 12(s+2.5) s (s² + 5s +11) A) It is desired to make the damping ratio (5) of the dominant closed-loop poles equal to (0.5) and to increase the undamped natural frequency (w) to (5 rad/sec) and the static velocity error constant to (K, = 60 sec-1). Design an appropriate compensator to meet all the performance specifications.? B) Check the stability of this system with compensator and without it? (
Consider a unity feedback system with the following open loop transfer function: G(s) = 5.7/[s(s+ 4) (s+20)] Using the second Ziegler-Nichols method design the PID controller G₂ (s) = K₂ (1+-+T₂5) The critical gain Kis a. 202.11 O b. 134.74 O c. 269.47 O d. 404.21 O e. 336.84
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BelowIn the unit feedback system given the shape, G(s),is given as. When a unit ramp is applied to the input of the system, 2% of the steady-state error and unit to the inputWhen the step is applied, it is desired that the percentage exceedance rate is 9.25% and the settling time is 0.58 s.1-In this case, which of the following is the approximate value of the constant a? 2-In this case, which of the following is the approximate value of the constant b? 3-Looking at the unit step response of the systemWhat is .peak time?
Q) In the negative feedback the low frequency and the high frequency * :with the feedback are (a) flf= fl /(1+AB) and fhf= fh /(1+Aß), where flf = low frequency with feedback (b) fhf= fh /(1+AB) and flf= fl (1+AB), where fhf = high frequency with feedback (c) flf= fl (1+AB) and fhf= fh (1+AB) (d) fhf= fh (1+AB) and flf= fl /(1+AB) O
Please solve all the questions in the picture and also of the negative feedback amplifier (in detail) Show the application of negative feedback reduces the fluctuation of the gain (dA/A) of theactual amplifier by the factor of (1+ A*beta ) where beta is the feedback factor. What is theadvantage. Take A = 13
lin Ас current_ VDD ✓ Tout SSEC $=67² Tin ( Bias Ckt omitted here) Unity Gain Frequency f₁ = Tout = 1 (unity) Current gain = AI Cgd_ifbk = 0 Cgs as r V₂ o di тель Tout 1. Derive an expression for ft of the fet shown above. (Please ignore the feedback current flowing through cgd) 2. Plot Ai vs frequency in the log-log scale and identify its slope (rate of decrease or increase vs. frequency) 3. Find an expression for ft in S.I. in terms of Cox.