25. Consider the torsionally loaded thin-walled member with a shear modulus (G) = 26e9N/m?.60N-m3.1mconstantthick ness += 0.04m0.8m0.4mFor this problem, what is the shear stress in the member?a. 92.5 N/m?b. 109.5 N/m?c. 230.5 N/m?d. 310.5 N/m?

Given data Shear modulus = G = 26 x 109 N/m2a = 0.8 mb = 0.4 mthickness = s =0.04 mlength = 3.2 mT =…

Answered: 25. Consider the torsionally loaded…

25. Consider the torsionally loaded thin-walled member with a shear modulus (G) = 26e9 N/m?. 6ON-m 3.1m censtant thick ness -0.04m 0.4m For this problem, what is the shear stress in the member?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Pravinbhai
a=2.1m (1) c = 2m b = 3.1m d = 1.8m P = 80 kN WHAT IS THE AXIAL STRESS IN ROD 1 ? ANSWER IN MPa ROUNDED-OFF TO 2 DECIMAL PLACES B dia. of rod 1: = 13mm dia of rod 2 = 11 mm
5. A brittle steel bar has the dimensions shown. Determine the maximum axial force P that can be applied not to exceed the allowable tensile stress of allow= 100 MPa. (Make sure to determine and account for the stress concentration factors). K 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0 P 0.1 0.2 0.3 W h W h 30 mm - 4.0 = 3.0 W Jang W h W h II = || 24 mm it P ht 2.0- = 1.5. T AL W W 12 mm 1.2- - 0.4 0.5 0.6 0.7 0.8 0.9 r 1.0 K 60 mm 3.2 3.0 2.8 2.6 2.4 2.2 2.0 0 0.1 r = 15 mm P 0.2 2r avg 0.3 2r P (w – 2r)t 0.4 0.5
(40 How A Rismatic steel bar of a Square cro ss section (look lo0)mm is loaoled by Compressive force P= 1300 KU, the bar has length 2.5 m, Eg=200GPay V=0.3,determine the shortening 8, the increase in the dimensions of cross Section , the change in Volume DV of the bar? loomm loomm
A cantilever beam of circular cross-section is made of alloy steel is subjected to a fluctuating load that varies from -F to 2F. Determine the minimum ultimate strength of the beam material which can withstand the fluctuating loads. The variable forces on the beam induce corresponding fluctuating stresses between + 48 N/mm2 to -24 N/mm?. Assume the following values. Yield strength = 0.55 ultimate strength, endurance stress = 0.45 ultimate strength. Take a factor of safety = 2. Use Soderberg relation in your design i) Calculate mean and alternating stress ii) Calculate endurance strength **Note: Please upload your handwritten working/solution to the link provided. Mean Stress in N/mm^2 ... Variable Stress in N/mm^2 ... Endurance Strength in N/mm^2 .. Ultimate Strength in N/mm^2..
Part 1. A composite assembly of length, L-375 mm, consisting of a steel (G-77 GPa) core (2) connected by rigid plates at the ends of an aluminum [G-35 GPa) tube (1) is shown. The aluminum tube has outside diameter D₁ - 50 mm and inside diameter d₁-30 mm. = 100 MPa, and the The solid steel core has diameter d₂-25 mm. The allowable shear stress of aluminum tube (1) is (rallow) allowable shear stress of steel core (2) is (Tallow)2= 135 MPa. Determine (a) the allowable torque T that can be applied to the composite shaft. (b) the corresponding torques produced in tube (1) and core (2). (c) the angle of twist produced by the allowable torque T. T D₁ L Calculate the polar moment of inertia, J₁, of the aluminum tube. Answer: J₁ (106) mm².
1. A solid square rod is cantilevered at one end. The rod is 0.8 m long and supports a completely reversing transverse load at the other end of 50 kN. The material is AISI 1060 hot-rolled steel (?? =370 MPa,?? =680 MPa ). Use a design factor of 2 and determine the dimensions of the square cross section for the following cases. Neglect any stress concentration. a. The rod must support this load for 100 cycles. b. The rod must support this load for 104 cycles. c. The rod must have infinite life.
5. (a) (b) (c) Koo D d An Aluminium alloy (6061-T6) circular tube (Fig.Q5) used for vehicle fittings is under axial compression. The tube has a length L = 5m, outer diameter D = 65mm and inner diameter d = 55mm. The Young's modulus of Aluminium alloy 6061-T6 is E= 68.9 GPa and yield strength ay = 276 MPa. Determine the buckling load with the Euler formula, assuming the tube to be pin-jointed at the two ends Determine the buckling load with the Euler formula, assuming the tube to be fixed at the two ends Assuming the tube to be pin-jointed at both ends, determine the length of the tube, below which the Euler formula is no longer valid Fig.Q5 L-
Calculate the stresses on the given round hollow frame.
Example/ A slab of steel in circular section with diameter 0.02m ana Tength 0.4m exposed into a tensile force F=3300 N with Modulus elasticity E =2x1010 Pa.
-8 in.- -8 in.- (a) (b) Which of the following best explains why cylinder (b) has a higher longitudinal stress in its walls compared to cylinder (a)? Assume the gauge pressure of the fluid inside the cylinder is non-zero. O Cylinder (b) is supported at two locations Cylinder (a) is not free to deform in its longitudinal direction The vertical (longitudinal) pressure in cylinder (a) is transferred directly to the [bottom] support, bypassing the cylinder walls None of the above the longitudinal stress for both cylinders is the same
Please provide the correct solution asap. Handwritten recommended