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The thin pressurized ring shown is an axisymmetric problem. The normal stresses as functions of rare σ, = 625 - 5625 1² 00=625 + 5625 2² σ₂ = 0 If the material constants are E = 29 x 10° lb/in² and v = 0.29, for 1 in ≤ r≤3 in, determine (a) the normal strains as functions of r and (b) the circum- ference at r = 3 in before and after the application of the pressure p.

The thin pressurized ring shown is an axisymmetric problem. The normal stresses as functions of rare σ, = 625 - 5625 1² 00=625 + 5625 2² σ₂ = 0 If the material constants are E = 29 x 10° lb/in² and v = 0.29, for 1 in ≤ r≤3 in, determine (a) the normal strains as functions of r and (b) the circum- ference at r = 3 in before and after the application of the pressure p.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Answers (a) er=15.30-250.2/r^2 , etheta=15.30+250.2/r^2 (b) delta c = 8.12x10^-4 in
6 in 2 in 0
Transcribed Image Text:6 in 2 in 0
The thin pressurized ring shown is an axisymmetric problem. The normal stresses as functions of r are 0,= 625 - 5625 12 σe = 625 + 5625 2 %₂=0 If the material constants are E = 29 X 10° lb/in² and v = r≤3 in, determine (a) the normal strains as functions of r and (b) the circum- ference at r = 3 in before and after the application of the pressure p. = 0.29, for 1 in S O 431- 431L. STAT 410 15/0
Transcribed Image Text:The thin pressurized ring shown is an axisymmetric problem. The normal stresses as functions of r are 0,= 625 - 5625 12 σe = 625 + 5625 2 %₂=0 If the material constants are E = 29 X 10° lb/in² and v = r≤3 in, determine (a) the normal strains as functions of r and (b) the circum- ference at r = 3 in before and after the application of the pressure p. = 0.29, for 1 in S O 431- 431L. STAT 410 15/0
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