2. An undamped mechanical oscillator whose with angular resonant frequency 5 rad/s is displaced a distance 0.03 m from its equilibrium position and released. Find: (a) the initial acceleration (b) the amplitude of the resulting motion (c) the maximum speed attained
2. An undamped mechanical oscillator whose with angular resonant frequency 5 rad/s is displaced a distance 0.03 m from its equilibrium position and released. Find: (a) the initial acceleration (b) the amplitude of the resulting motion (c) the maximum speed attained
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:2. An undamped mechanical oscillator whose with angular resonant frequency 5 rad/s
is displaced a distance 0.03 m from its equilibrium position and released.
Find:
(a) the initial acceleration
(b) the amplitude of the resulting motion
(c) the maximum speed attained

Transcribed Image Text:b)
V
2₂
[
&
Jementand
↑
고
2-5X
6
TO
I ma
1
0
Wo = 5 vad/s
-
SX
11
J
S
A = x₂
Хо
Say
(re)v=
(re) Vmax = WA
8
.03m
Wo = √e oma.
W.²
)
0.03
X= де ошь
Vaj Beowt
F
m
iW Acasht
وام
-x W₂²
%
5
✓
= 0.75 msz
T
= -;WA (sin lit t; cau lot)
6
B
when coulit = 1
- SX 0.63 = 0.15 ms
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