Answered: 238U decays spontaneously by a emission… | bartleby

Related questions

Question

²³⁸U decays spontaneously by a emission to ²³⁴Th. Calculate (a) the total energy released by this process and (b) the recoil velocity of the ²³⁴Th nucleus. The atomic masses are 238.050788 u for ²³⁸U and 234.043601 u for ²³⁴Th.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Find the Energy emitted in the Alpha Decay of 238U in MeV. m(238U) = 238.050784 m(234Th) = 234.0436 m(4He) = 4.002602
Hand written solutions are strictly prohibited.
39.8 An atom of uranium-235 (atomic mass: m(23U) cays to thorium-231 (atomic mass: 231. 00 Th) = 231.03630 u) emission of an 235.04392 u) de- 92 via the a particle (nuclear 4.00151 u). m(ža) c = 2.998 x 108 m s-1. mass: Use %D (a) What is the binding energy of an 235U nucleus (in J)? 92 (b) What is the binding energy of a 231 Th nucleus (in J)? 90 (c) What is the binding energy of an a particle (in J)? (d) What is the maximum possible ki- netic energy (in J) of the a particle emitted during this decay? (Hint: what is the difference between the mass of 23°U and the total mass of 92 231 Th and an a particle?) 90 (e) Whatis the maximum velocity of the emitted a particle?
Consider the following a-decay of the Uranium nucleus 236 U → 332Th + a. 90 (a) Show how the mass number (Aa) and atomic number (Za) of the alpha particle are obtained from this equation. (b) Calculate the Q-value (Qa) of the reaction. (c) Calculate the speed va = √2MQ of the alpha particle after it has been ejected from the parent nucleus, in terms of the speed of light c. M = -, mp and ma are the atomic masses (ma+mp) x ma mp of the daugher nucleus and the alpha particle, respectively. (d) Calculate the classical turning radius Re= 2Zpe²/Qa, where Zp is the atomic number of the daughter nucleus, and e² = 1.44 MeV. fm. (e) Calculate the decay probability Pa that the alpha particle will tunnel through the barrier. HINT: In calculating the probability, use the fact that ħc=197.327 MeV fm. The formula to use is given on page 5.
A nucleus of 238 Np captures a thermal neutron to form a nucleus of 239 Np . What is the excitation energy ( to 1 dp ) in MeV for this process ?
(a) In addition to uranium, plutonium is also a well-suited starting product for the release of energy through nuclear fission. If you bombard a ²32Pu nucleus with a neutron the fission products 94 barium ¹Ba and strontium 3Sr are formed. 56 (i) Write down the full equation of the reaction. (ii) Calculate the reaction energy in eV units. Note that m(232Pu) = 239.052162u, 94 m(¹Ba) = 143.922955u, and m(Sr) = 93.915356u. (iii) Explain what triggers a chain reaction with 232 Pu. 94
A nucleus of 238 Np captures a thermal neutron to form a nucleus of 23⁹Np. What is the excitation energy (to 1 dp) in MeV for this process?
Consider the fission reaction 141 n + U -> 235, 92U syXe + 92 38Sr +3n The masses of the components are 235 235.04393 세 xe| 140.여 2678 92 5 91.911 038 n 1.00 866 U Find the energy released in MeV Use the editor to format your answer
When a nucleus decays, the daughter nucleus can be in an excited state. The 93/43Tc nucleus (molar mass 92.910 2 g/mol) in the ground state decays by electron capture and e+ emission to energy levels of the daughter (molar mass 92.906 8 g/mol in the ground state) at 2.44 MeV, 2.03 MeV, 1.48 MeV, and 1.35 MeV. (a) Identify the daughter nuclide. (b) To which of the listed levels of the daughter are electron capture and e+ decay of 93/43Tc allowed?