235/92U+1/0n→ 140/54Xe+94/38Sr+2 1/0n mass of 235/92U=235.04393u mass of 140/54Xe=139.92144u mass of 94/38Sr=93.91523u mass of 1/0n=1.008665u Part A: What is the reaction energy Q of this reaction? Use c2=931.5MeV/u. Part B: Using fission, what mass m of uranium-235 would be necessary to supply all of the energy that the United States uses in a year, roughly 1.0×10^19J ?
235/92U+1/0n→ 140/54Xe+94/38Sr+2 1/0n mass of 235/92U=235.04393u mass of 140/54Xe=139.92144u mass of 94/38Sr=93.91523u mass of 1/0n=1.008665u Part A: What is the reaction energy Q of this reaction? Use c2=931.5MeV/u. Part B: Using fission, what mass m of uranium-235 would be necessary to supply all of the energy that the United States uses in a year, roughly 1.0×10^19J ?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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235/92U+1/0n→ 140/54Xe+94/38Sr+2 1/0n
mass of 235/92U=235.04393u
mass of 140/54Xe=139.92144u
mass of 94/38Sr=93.91523u
mass of 1/0n=1.008665u
Part A: What is the reaction energy Q of this reaction? Use c2=931.5MeV/u.
Part B:
Using fission, what mass m of uranium-235 would be necessary to supply all of the energy that the United States uses in a year, roughly 1.0×10^19J ?
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