The indium isotope 115/49 I n captures an electron and becomes the cadmium isotope 115/48 C d, as shown in the nuclear reaction below. 115/49 I n + ? ⟶ 115/48 C d What kind of particle is emitted in this decay, as denoted by the question mark?
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The indium isotope 115/49 I n captures an electron and becomes the cadmium isotope 115/48 C d, as shown in the nuclear reaction below.
115/49 I n + ? ⟶ 115/48 C d
What kind of particle is emitted in this decay, as denoted by the question mark?
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- The isotope palladium-112 undergoes beta decay. Write the reaction equation and determine the identity of the daughter nucleus. 112 46 Pd → 112 47 Ag + 0 −1 e 112 46 Pd → 111 47 Ag + 0 −1 e 112 46 Pd → 112 45 Rh + 0 −1 e 112 46 Pd → 113 47 Ag + 0 −1 e 112 46 Pd → 111 45 Rh + 0 −1 eUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m = 1.67493x10-27 kg = 1.008665 u = 939.57 MeV/c² . ¹H: mH = 1.67353x10-27 kg = 1.007825 u = 938.78 MeV/c² 1 1 u = 1.6605x10-27 kg = 931.5 MeV/c² . Consider the following decay: 239 Pu 235 U+ a. 239 Pu has a mass of 239.0521634 u, 235 U has a mass of 235.0439299 u, and a has a mass of 4.002603 u. 94 92 94 92 Determine the disintegration energy (Q-value) in MeV. Q = Determine the binding energy (in MeV) for 239 Pu. 94 EB =Fill in the missing isotope for the following decay process. ¹4C → ? + e +v 6 A B E He 10 Be 14B 14 * 14N
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