| What statement can be made about the masses of atoms in the above reaction? A. m(U) > m('Ba) + m(Kr) + 2m(¿n) B. m(U)

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The uranium isotope 235U can fission—break into two smaller-mass
components and free neutrons—if it is struck by a free neutron. A typical reaction is
                          1/0n + 235/92U → 141/56Ba + 92/36Kr + 3/1/0n
As you can see, the subscripts (the number of protons) and the superscripts (the number of nucleons) “balance” before and after the fission event; there is no change in the number of protons or neutrons. Significant energy is released in this reaction. If a fission event happens in a large chunk of 235U, the neutrons released may induce the fission of other 235U atoms, resulting in a chain reaction. This is how a nuclear reactor works. The number of neutrons required to create a stable nucleus increases with atomic number. When the heavy 235U nucleus fissions, the lighter reaction products are thus neutron rich and are likely unstable. Many of the short-lived radioactive nuclei used in medicine are produced in fission reactions in nuclear reactors.

 

| What statement can be made about the masses of atoms in
the above reaction?
A. m(U) > m('Ba) + m(Kr) + 2m(¿n)
B. m(U) <m('Ba) + m(Kr) + 2m(on)
C. m(U) = m(Ba) + m(Kr) + 2m(,n)
D. m(²3¿U) = m('Ba) + m(¾Kr) + 3m(ón)
(235
235
141
56
141-
56
141-
56
235
Transcribed Image Text:| What statement can be made about the masses of atoms in the above reaction? A. m(U) > m('Ba) + m(Kr) + 2m(¿n) B. m(U) <m('Ba) + m(Kr) + 2m(on) C. m(U) = m(Ba) + m(Kr) + 2m(,n) D. m(²3¿U) = m('Ba) + m(¾Kr) + 3m(ón) (235 235 141 56 141- 56 141- 56 235
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