1. Let's do fun things- Integration! [Antiparticle of a particle has the same mass but opposite charge to that corresponding particle. As particle and antiparticle annihilate into photons/energy whenever they meet, antiparticles are contained in special vacuum chamber with the help of electric and magnetic fields. For the sake of simplicity, we ignore magnetic fields and gravitation here.] Figure 1: You have a finite line (Length L) of positive charges, Q. Figure 2: Now suppose, to complicate your life, you made a square of length 1m with those lines of charges. AB and BC line have +Q charge while CD and AD line have negative charges, -Q. And then you place a positron in the center. R L Figure 1: 1 m D Figure 2: B 1 (a) Show that, in figure 1, the magnitude of electrical field at point P is E = Απέρ R√ R² + (4)² [6] (b) Using the above formula of electric field, find the total force, F, on the positron. From the direction of F, show that no one can save the positron from being eliminated at vertex D. [6] (c) Seeing your failure of saving the positron, your friend suggested that BC and CD line should be exchanged. Should you trust your friend? Explain Mathematically. [6] 1 2. Dipole Again Two same magnitude but opposite charges are kept 2d distance apart like in the following figure. 0 P 2d +9 1 [6] [3] (a) Find the exact electric field at point P in terms of r and d. (b) Show that if r >> d, then electric field is proportional to (c) If you insert r = 0 at the answer (b), that is at the midpoint, you will get electric field is infinite which is impossible. What's wrong? [3]
1. Let's do fun things- Integration! [Antiparticle of a particle has the same mass but opposite charge to that corresponding particle. As particle and antiparticle annihilate into photons/energy whenever they meet, antiparticles are contained in special vacuum chamber with the help of electric and magnetic fields. For the sake of simplicity, we ignore magnetic fields and gravitation here.] Figure 1: You have a finite line (Length L) of positive charges, Q. Figure 2: Now suppose, to complicate your life, you made a square of length 1m with those lines of charges. AB and BC line have +Q charge while CD and AD line have negative charges, -Q. And then you place a positron in the center. R L Figure 1: 1 m D Figure 2: B 1 (a) Show that, in figure 1, the magnitude of electrical field at point P is E = Απέρ R√ R² + (4)² [6] (b) Using the above formula of electric field, find the total force, F, on the positron. From the direction of F, show that no one can save the positron from being eliminated at vertex D. [6] (c) Seeing your failure of saving the positron, your friend suggested that BC and CD line should be exchanged. Should you trust your friend? Explain Mathematically. [6] 1 2. Dipole Again Two same magnitude but opposite charges are kept 2d distance apart like in the following figure. 0 P 2d +9 1 [6] [3] (a) Find the exact electric field at point P in terms of r and d. (b) Show that if r >> d, then electric field is proportional to (c) If you insert r = 0 at the answer (b), that is at the midpoint, you will get electric field is infinite which is impossible. What's wrong? [3]
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.10CQ: Consider two electric dipoles in empty space. Each dipole has zero net charge. (a) Does an electric...
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![1. Let's do fun things- Integration!
[Antiparticle of a particle has the same mass but opposite charge to that corresponding particle.
As particle and antiparticle annihilate into photons/energy whenever they meet, antiparticles are
contained in special vacuum chamber with the help of electric and magnetic fields. For the sake
of simplicity, we ignore magnetic fields and gravitation here.]
Figure 1: You have a finite line (Length L) of positive charges, Q.
Figure 2: Now suppose, to complicate your life, you made a square of length 1m with those lines
of charges. AB and BC line have +Q charge while CD and AD line have negative charges, -Q.
And then you place a positron in the center.
R
L
Figure 1:
1 m
D
Figure 2:
B
1
(a) Show that, in figure 1, the magnitude of electrical field at point P is E =
Απέρ R√
R² + (4)²
[6]
(b) Using the above formula of electric field, find the total force, F, on the positron. From the
direction of F, show that no one can save the positron from being eliminated at vertex D. [6]
(c) Seeing your failure of saving the positron, your friend suggested that BC and CD line should
be exchanged. Should you trust your friend? Explain Mathematically.
[6]
1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45e4ce91-de02-4f34-a479-fb0021264e1d%2Fc0f9828a-d724-4ce9-981a-04acbce62070%2Fqicums7_processed.png&w=3840&q=75)
Transcribed Image Text:1. Let's do fun things- Integration!
[Antiparticle of a particle has the same mass but opposite charge to that corresponding particle.
As particle and antiparticle annihilate into photons/energy whenever they meet, antiparticles are
contained in special vacuum chamber with the help of electric and magnetic fields. For the sake
of simplicity, we ignore magnetic fields and gravitation here.]
Figure 1: You have a finite line (Length L) of positive charges, Q.
Figure 2: Now suppose, to complicate your life, you made a square of length 1m with those lines
of charges. AB and BC line have +Q charge while CD and AD line have negative charges, -Q.
And then you place a positron in the center.
R
L
Figure 1:
1 m
D
Figure 2:
B
1
(a) Show that, in figure 1, the magnitude of electrical field at point P is E =
Απέρ R√
R² + (4)²
[6]
(b) Using the above formula of electric field, find the total force, F, on the positron. From the
direction of F, show that no one can save the positron from being eliminated at vertex D. [6]
(c) Seeing your failure of saving the positron, your friend suggested that BC and CD line should
be exchanged. Should you trust your friend? Explain Mathematically.
[6]
1
![2. Dipole Again
Two same magnitude but opposite charges are kept 2d distance apart like in the following figure.
0
P
2d
+9
1
[6]
[3]
(a) Find the exact electric field at point P in terms of r and d.
(b) Show that if r >> d, then electric field is proportional to
(c) If you insert r = 0 at the answer (b), that is at the midpoint, you will get electric field is
infinite which is impossible. What's wrong?
[3]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45e4ce91-de02-4f34-a479-fb0021264e1d%2Fc0f9828a-d724-4ce9-981a-04acbce62070%2F8sm5p02_processed.png&w=3840&q=75)
Transcribed Image Text:2. Dipole Again
Two same magnitude but opposite charges are kept 2d distance apart like in the following figure.
0
P
2d
+9
1
[6]
[3]
(a) Find the exact electric field at point P in terms of r and d.
(b) Show that if r >> d, then electric field is proportional to
(c) If you insert r = 0 at the answer (b), that is at the midpoint, you will get electric field is
infinite which is impossible. What's wrong?
[3]
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