2. Assume the section below has cracked and the transformed area method must be applied to compute bending stresses. Locate the neutral axis of the transformed section. Draw the transformed section. The image below is not to scale. You do not need to compute the moment of inertia for the transformed section. f= = 3000 psi, fy = 60000 psi, n = 8. The area of a #9 bar cross section is 1.0 in². 4 #9 .. 12in 18 in. 3 in. 21 in.

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Chapter6: Vertical Stress Increase In Soil
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Problem 6.4P: Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine...
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2. Assume the section below has cracked and the transformed area method must be applied to compute bending
stresses. Locate the neutral axis of the transformed section. Draw the transformed section. The image below is
not to scale. You do not need to compute the moment of inertia for the transformed section.
f = 3000 psi, fy = 60000 psi, n = 8. The area of a #9 bar cross section is 1.0 in².
4 #9
12in
18 in.
3 in.
21 in.
Transcribed Image Text:2. Assume the section below has cracked and the transformed area method must be applied to compute bending stresses. Locate the neutral axis of the transformed section. Draw the transformed section. The image below is not to scale. You do not need to compute the moment of inertia for the transformed section. f = 3000 psi, fy = 60000 psi, n = 8. The area of a #9 bar cross section is 1.0 in². 4 #9 12in 18 in. 3 in. 21 in.
Centroid of a composite area
Σyi Ai
ΣΑ;
First moment of area for a cross section (about x-axis)
Qx = yA
Moment of inertia for a rectangle, about neutral x-axis
y
I ==—= 2 bh³
12
Parallel axis theorem
I = Σ(Ī₂ + Ad?)
Modulus of rupture for a concrete cross section
fr = 7.52√ √f
Linear stress distribution in a cross section
f = My
I
Maximum moment for a simply supported beam under a distributed load
Mmax
n =
=
Modular ratio
Es
Ec
w1²
8
At ultimate, assumed compression force in a concrete section
C = 0.85f Ac
At ultimate, assumed tension force in a concrete section
T = Asfy
Nominal moment for a concrete section
Mn = T (d - YA) = C(d - YAc)
Transcribed Image Text:Centroid of a composite area Σyi Ai ΣΑ; First moment of area for a cross section (about x-axis) Qx = yA Moment of inertia for a rectangle, about neutral x-axis y I ==—= 2 bh³ 12 Parallel axis theorem I = Σ(Ī₂ + Ad?) Modulus of rupture for a concrete cross section fr = 7.52√ √f Linear stress distribution in a cross section f = My I Maximum moment for a simply supported beam under a distributed load Mmax n = = Modular ratio Es Ec w1² 8 At ultimate, assumed compression force in a concrete section C = 0.85f Ac At ultimate, assumed tension force in a concrete section T = Asfy Nominal moment for a concrete section Mn = T (d - YA) = C(d - YAc)
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