2. Ammonium perchlorate reacts with aluminum according to the balanced reaction below. 3 NHACIO. (s) + 3 Al (s)→3 NO(g) + 1 Al2O(s) + 6H₂O(g) +1 AIC (g) a. If 67.1 g of ammonium perchlorate were to react with 10.0 g of aluminum, which substance would be the limiting reactant? b. How many liters of each gaseous product are formed, if the reaction occurs at STP? C. How many grams of excess reactant remains after the reaction is complete?

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**Reaction of Ammonium Perchlorate with Aluminum**

In this section, we will explore a chemical reaction involving ammonium perchlorate and aluminum. The balanced chemical equation for this reaction is provided below:

\[ 3 \text{NH}_4\text{ClO}_4(s) + 3 \text{Al} (s) \rightarrow 3 \text{NO} (g) + 1 \text{Al}_2\text{O}_3(s) + 6 \text{H}_2\text{O} (g) + 1 \text{AlCl}_3(g) \]

**Problem Statement:**

a. If 67.1 g of ammonium perchlorate were to react with 10.0 g of aluminum, which substance would be the limiting reactant?

b. How many liters of each gaseous product are formed, if the reaction occurs at STP?

c. How many grams of excess reactant remains after the reaction is complete?

**Detailed Breakdown:**

1. **Determine the Limiting Reactant:**
   - Calculate the molar masses of NH4ClO4 and Al.
   - Convert the given masses of NH4ClO4 and Al to moles.
   - Use stoichiometry to determine which reactant is limiting based on the balanced equation proportions.

2. **Volume of Gaseous Products:**
   - Identify the gaseous products from the equation.
   - Calculate the total moles of each gaseous product using the limiting reactant.
   - Convert the moles of gases to volume at STP (Standard Temperature and Pressure) using the ideal gas law (1 mole of gas = 22.4 liters at STP).

3. **Excess Reactant Remaining:**
   - Calculate how much of the excess reactant is consumed in the reaction using stoichiometry.
   - Subtract the consumed amount from the original amount to find the remaining mass of the excess reactant.

This exercise illustrates fundamental concepts in stoichiometry, limiting reactants, ideal gas law calculations, and conservation of mass in chemical reactions. These concepts are essential for a solid understanding of chemical reactions and their quantitative aspects.
Transcribed Image Text:**Reaction of Ammonium Perchlorate with Aluminum** In this section, we will explore a chemical reaction involving ammonium perchlorate and aluminum. The balanced chemical equation for this reaction is provided below: \[ 3 \text{NH}_4\text{ClO}_4(s) + 3 \text{Al} (s) \rightarrow 3 \text{NO} (g) + 1 \text{Al}_2\text{O}_3(s) + 6 \text{H}_2\text{O} (g) + 1 \text{AlCl}_3(g) \] **Problem Statement:** a. If 67.1 g of ammonium perchlorate were to react with 10.0 g of aluminum, which substance would be the limiting reactant? b. How many liters of each gaseous product are formed, if the reaction occurs at STP? c. How many grams of excess reactant remains after the reaction is complete? **Detailed Breakdown:** 1. **Determine the Limiting Reactant:** - Calculate the molar masses of NH4ClO4 and Al. - Convert the given masses of NH4ClO4 and Al to moles. - Use stoichiometry to determine which reactant is limiting based on the balanced equation proportions. 2. **Volume of Gaseous Products:** - Identify the gaseous products from the equation. - Calculate the total moles of each gaseous product using the limiting reactant. - Convert the moles of gases to volume at STP (Standard Temperature and Pressure) using the ideal gas law (1 mole of gas = 22.4 liters at STP). 3. **Excess Reactant Remaining:** - Calculate how much of the excess reactant is consumed in the reaction using stoichiometry. - Subtract the consumed amount from the original amount to find the remaining mass of the excess reactant. This exercise illustrates fundamental concepts in stoichiometry, limiting reactants, ideal gas law calculations, and conservation of mass in chemical reactions. These concepts are essential for a solid understanding of chemical reactions and their quantitative aspects.
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