2-naphthol benzoic acid sodium benzoate ethyl p-aminobenzoate biphenyl H2N. OH Na 2.70 1.87 -2.27 1.86 4.01 Figure 1. octanol-water partition coefficients log10Poctanol water for organic compounds We can use this to calculate the distribution of a compound between the two phases. For example, take 2-naphthol: the value of log 10P for this compound is calculated to be 2.70. [2 – naphthol]octanol [2-naphthol]water 102.70 = 5.0 × 10² The percentage of 2-naphthol in water is given by: [2-naphthol]water [2-naphthol]octanol + [2-naphthol]water %[2-naphthol],water = 100 ×
2-naphthol benzoic acid sodium benzoate ethyl p-aminobenzoate biphenyl H2N. OH Na 2.70 1.87 -2.27 1.86 4.01 Figure 1. octanol-water partition coefficients log10Poctanol water for organic compounds We can use this to calculate the distribution of a compound between the two phases. For example, take 2-naphthol: the value of log 10P for this compound is calculated to be 2.70. [2 – naphthol]octanol [2-naphthol]water 102.70 = 5.0 × 10² The percentage of 2-naphthol in water is given by: [2-naphthol]water [2-naphthol]octanol + [2-naphthol]water %[2-naphthol],water = 100 ×
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![2-naphthol
benzoic acid
sodium benzoate
ethyl p-aminobenzoate
biphenyl
H2N.
Na
2.70
1.87
-2.27
1.86
4.01
Figure 1. octanol-water partition coefficients log1,Poctanol water for organic compounds
We can use this to calculate the distribution of a compound between the two phases. For
example, take 2-naphthol: the value of log 10P for this compound is calculated to be 2.70.
[2 – naphthol]octanol
[2-naphthol]water
102.70 = 5.0 × 10²
The percentage of 2-naphthol in water is given by:
[2-naphthol]water
[2-naphthol]octanol + [2-naphthol]water
%[2-naphthol],water = 100 x
Assuming partition between equal volumes of organic and aqueous phase, what percentage of
each of the compounds will be present in the water layer (show working)?
Benzoic acid
Ethyl p-aminobenzoate
Biphenyl](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2932a05-99f3-41c1-989e-7dbca32c3377%2F42a5703e-db50-4ac4-9dd3-2c5547a5c698%2Fynizf5b_processed.png&w=3840&q=75)
Transcribed Image Text:2-naphthol
benzoic acid
sodium benzoate
ethyl p-aminobenzoate
biphenyl
H2N.
Na
2.70
1.87
-2.27
1.86
4.01
Figure 1. octanol-water partition coefficients log1,Poctanol water for organic compounds
We can use this to calculate the distribution of a compound between the two phases. For
example, take 2-naphthol: the value of log 10P for this compound is calculated to be 2.70.
[2 – naphthol]octanol
[2-naphthol]water
102.70 = 5.0 × 10²
The percentage of 2-naphthol in water is given by:
[2-naphthol]water
[2-naphthol]octanol + [2-naphthol]water
%[2-naphthol],water = 100 x
Assuming partition between equal volumes of organic and aqueous phase, what percentage of
each of the compounds will be present in the water layer (show working)?
Benzoic acid
Ethyl p-aminobenzoate
Biphenyl
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