looking at this reaction (first image), The second image shows the 13C NMR spectrum of the 2-acetnaphthone which is the starting material and an 13C NMR spectrum obtained for the reaction product:Based a comparison of the two 13C NMR spectra, is product A or product B the major product of the reaction? - Explain your reasoning. 2-AcetnaphthoneNaBH4CH3OHProduct AOHorProduct B? 20013C NMR spectrum of the product:2001501501001005050[ppm]0 [ppm]F25 [rel201510G014 [rel]12ОТ89420

NaBH4 reduces aldehyde/ketone to primary/secondary alcohol

Answered: 2-Acetnaphthone NaBH4 CH₂OH Product A…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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looking at this reaction (first image),

The second image shows the ¹³C NMR spectrum of the 2-acetnaphthone which is the starting material and an ¹³C NMR spectrum obtained for the reaction product:

Based a comparison of the two ¹³C NMR spectra, is product A or product B the major product of the reaction? - Explain your reasoning.

2-Acetnaphthone
NaBH4
CH3OH
Product A
OH
or
Product B
?

200
13C NMR spectrum of the product:
200
150
150
100
100
50
50
[ppm]
0 [ppm]
F
25 [rel
20
15
10
G
0
14 [rel]
12
ОТ
8
9
4
2
0

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