5 Compound X IS a monocyclic and has molecular formula Cy Ho CID. The IR spectrum for compound X Shows a strong absorption at 1790cm². Compouna X does not show an absorption 9t 2950 (m". Which one is compound X? DH 1. CI OCH3
Please answer question 5,7 and 9 step-by-step thank you.
(5) C4H5ClO
DBE = 4 + 1 - 5/2 - 1/2 = 2
IR
1790 cm-1 : C=O stretching (presence of carbonyl group)
In the given structures carbonyl group is present for option "a" and compound "c".
There is no IR stretching at 2750 cm-1. Which indicates no aldehydic C-H stretching.
Possible structure is option "c".
(7)
More deshielded the proton higher will be the chemical shift.
In option "a" the terminal proton near 2 Cl atoms will give peak at highest chemical shift because two electronegative Cl groups will deshielded the proton at high extent than one Cl at different positions in option "d"
Options "b" , "c" and "e" are different from "a" because no proton is present at the carbon where 2 Cl attached in "b" , "c" and "e".
Possible structure is option "a".
(9)C7H14O
DBE = 7 + 1 - 14/2 = 1
1710 cm-1 : C=O stretching (presence of carbonyl group)
2950 cm-1 : sp3 C-H stretching
In 1H NMR only 7 hydrogens given but total 14 hydrogens present, it means symmetric molecule.
Possible structure is option "b".
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