18. Considering the shown reaction that occurs in the skeletal muscle, which of the following statements is true? ATP H KEXK H HO TOH H OH H HO CH₂OH он H QH H H OH он A B A. The only fate of the product B is to undergo glycolysis B. Accumulation of B would inhibit the reaction C. Both A and B D. Neither A nor B

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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### Glycolysis and Skeletal Muscle Reactions

**Question 18:** Considering the shown reaction that occurs in the skeletal muscle, which of the following statements is true?

**Diagram Description:**

The diagram depicts a chemical reaction involving two molecular structures labeled A and B. 

- Molecule A (on the left) is a cyclic molecule with a hydroxyl group (–OH) attached to each carbon atom. The structure is a ring form typical of glucose. 
- Molecule B (on the right) is similar to A but has a phosphate group (–P) attached to the sixth carbon atom, indicating it is likely glucose-6-phosphate.

The reaction:

- Molecule A is phosphorylated to become Molecule B.
- ATP (adenosine triphosphate) is converted to ADP (adenosine diphosphate) in the process, donating a phosphate group to Molecule A.

**Answer Options:**
A. The only fate of the product B is to undergo glycolysis.
B. Accumulation of B would inhibit the reaction.
C. Both A and B.
D. Neither A nor B.

---

This question asks about the metabolic fate of glucose-6-phosphate in skeletal muscle and the regulation of its formation. Select the correct theoretical statement based on your understanding of muscle metabolism and glycolysis.
Transcribed Image Text:### Glycolysis and Skeletal Muscle Reactions **Question 18:** Considering the shown reaction that occurs in the skeletal muscle, which of the following statements is true? **Diagram Description:** The diagram depicts a chemical reaction involving two molecular structures labeled A and B. - Molecule A (on the left) is a cyclic molecule with a hydroxyl group (–OH) attached to each carbon atom. The structure is a ring form typical of glucose. - Molecule B (on the right) is similar to A but has a phosphate group (–P) attached to the sixth carbon atom, indicating it is likely glucose-6-phosphate. The reaction: - Molecule A is phosphorylated to become Molecule B. - ATP (adenosine triphosphate) is converted to ADP (adenosine diphosphate) in the process, donating a phosphate group to Molecule A. **Answer Options:** A. The only fate of the product B is to undergo glycolysis. B. Accumulation of B would inhibit the reaction. C. Both A and B. D. Neither A nor B. --- This question asks about the metabolic fate of glucose-6-phosphate in skeletal muscle and the regulation of its formation. Select the correct theoretical statement based on your understanding of muscle metabolism and glycolysis.
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