16- II CH3-c -NH2 + H2O → H2S + CH;-C -NH2 The hydrolysis of thioacetamide is used to generate H,S as shown by the equation above. The rate of the reaction is given by the rate law as follows: II rate = k[H*][CH3-c-NH2] Consider a solution which is 0.10 molar in H+ and 0.10 molar in thioacetamide at 25° for each of the changes listed in (1), (2) and (3) below, state whether (a) the rate of reaction increases, decreases or remains the same. (b) the numerical value of k increases, decreases or remains the same. (1) Sodium acetate is added to the solution. (2) The solution is heated to 75°C. (3) Water is added to the solution. Give a brief explanation for each of your answers.

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16-
S
||
CH;-C -NH, + H0 → H,S + CH;-C -NH,
The hydrolysis of thioacetamide is used to generate H2S as shown by the equation above. The rate of
the reaction is given by the rate law as follows:
||
rate = k[H*][CH3-C -NH2]
Consider a solution which is 0.10 molar in H+ and 0.10 molar in thioacetamide at 25° for each of the
changes listed in (1), (2) and (3) below, state whether
(a) the rate of reaction increases, decreases or remains the same.
(b) the numerical value of k increases, decreases or remains the same.
(1) Sodium acetate is added to the solution.
(2) The solution is heated to 75°C.
(3) Water is added to the solution.
Give a brief explanation for each of your answers.
Transcribed Image Text:16- S || CH;-C -NH, + H0 → H,S + CH;-C -NH, The hydrolysis of thioacetamide is used to generate H2S as shown by the equation above. The rate of the reaction is given by the rate law as follows: || rate = k[H*][CH3-C -NH2] Consider a solution which is 0.10 molar in H+ and 0.10 molar in thioacetamide at 25° for each of the changes listed in (1), (2) and (3) below, state whether (a) the rate of reaction increases, decreases or remains the same. (b) the numerical value of k increases, decreases or remains the same. (1) Sodium acetate is added to the solution. (2) The solution is heated to 75°C. (3) Water is added to the solution. Give a brief explanation for each of your answers.
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