The rate law for the mechanism below is I2(g) 21) K1, fast I(g) + CO(g) = COI (g) K2, fast COI (g) + I(g) → COI2(g) k3, slow rate = K10.5k3 [COI][12]0.5 rate = K1 K2k3 [CO][12] rate = k3[COI][I] rate = K10.5 K2k3 [CO][12]0.5[1] rate = K2k3[CO][1]²
The rate law for the mechanism below is I2(g) 21) K1, fast I(g) + CO(g) = COI (g) K2, fast COI (g) + I(g) → COI2(g) k3, slow rate = K10.5k3 [COI][12]0.5 rate = K1 K2k3 [CO][12] rate = k3[COI][I] rate = K10.5 K2k3 [CO][12]0.5[1] rate = K2k3[CO][1]²
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 111QRT
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![The rate law for the mechanism below is
I2(g) 21g) K₁, fast
I(g) + CO(g) = COI (g) K2, fast
COIg) + Ig) →>> COI2(g) K3, slow
rate = K10.5k3 [COI][12]0.5
rate = K₁ K2k3 [CO][12]
rate = K3[COI][I]
☐ rate = K₁0.5 K2k3 [CO][12] 0.5[1]
rate = K2k3[CO][1]²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32973613-eba3-44fb-9613-24c76949a18d%2Ff084fa0c-db8d-4a3f-8fb9-17d416af0f15%2Frg22cro_processed.png&w=3840&q=75)
Transcribed Image Text:The rate law for the mechanism below is
I2(g) 21g) K₁, fast
I(g) + CO(g) = COI (g) K2, fast
COIg) + Ig) →>> COI2(g) K3, slow
rate = K10.5k3 [COI][12]0.5
rate = K₁ K2k3 [CO][12]
rate = K3[COI][I]
☐ rate = K₁0.5 K2k3 [CO][12] 0.5[1]
rate = K2k3[CO][1]²
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