15. A reaction was found to be third order in A. Increasing the concentration of A by a factor of 3 will cause the reaction rate to increase by a factor of

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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**Question 15: Reaction Order and Rate Increase**

15. A reaction was found to be third order in A. Increasing the concentration of A by a factor of 3 will cause the reaction rate to increase by a factor of ______.

**Explanation:**
In chemical kinetics, the order of a reaction with respect to a particular reactant can determine how changes in the concentration of that reactant affect the reaction rate. For a reaction that is third order with respect to reactant A, the rate of the reaction is proportional to the concentration of A raised to the power of 3.

Given the relationship:

\[ \text{Rate} = k [A]^3 \]

where \(\text{Rate}\) is the reaction rate, \(k\) is the rate constant, and \([A]\) is the concentration of reactant A.

If the concentration of A is increased by a factor of 3, the new concentration of A would be \(3[A]\). Substituting this into the rate equation:

\[ \text{New Rate} = k (3[A])^3 = k \cdot 27[A]^3 \]

This simplifies to:

\[ \text{New Rate} = 27 \times (\text{Original Rate}) \]

Therefore, the reaction rate will increase by a factor of 27 when the concentration of A is increased by a factor of 3.
Transcribed Image Text:**Question 15: Reaction Order and Rate Increase** 15. A reaction was found to be third order in A. Increasing the concentration of A by a factor of 3 will cause the reaction rate to increase by a factor of ______. **Explanation:** In chemical kinetics, the order of a reaction with respect to a particular reactant can determine how changes in the concentration of that reactant affect the reaction rate. For a reaction that is third order with respect to reactant A, the rate of the reaction is proportional to the concentration of A raised to the power of 3. Given the relationship: \[ \text{Rate} = k [A]^3 \] where \(\text{Rate}\) is the reaction rate, \(k\) is the rate constant, and \([A]\) is the concentration of reactant A. If the concentration of A is increased by a factor of 3, the new concentration of A would be \(3[A]\). Substituting this into the rate equation: \[ \text{New Rate} = k (3[A])^3 = k \cdot 27[A]^3 \] This simplifies to: \[ \text{New Rate} = 27 \times (\text{Original Rate}) \] Therefore, the reaction rate will increase by a factor of 27 when the concentration of A is increased by a factor of 3.
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