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Write the rate law for the following reactions, assuming ea Give the units of kA for each rate law, keeping in mind that reactions are heterogeneous:

Write the rate law for the following reactions, assuming ea Give the units of kA for each rate law, keeping in mind that reactions are heterogeneous:

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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**Problem 3** Write the rate law for the following reactions, assuming each reaction follows an elementary rate law. Give the units of \( k_A \) for each rate law, keeping in mind that some reactions are homogeneous and some reactions are heterogeneous: **(A)** \( \text{C}_2\text{H}_4 + \frac{1}{2} \text{O}_2 \rightarrow \begin{array}{c} \\ O \\ | \\ \text{CH}_2 - \text{CH}_2 \end{array} \) **(B)** \( \text{nC}_4\text{H}_{10} \rightleftharpoons \text{iC}_4\text{H}_{10} \) **Explanation of Diagram:** - Reaction **(A)** involves ethylene (\(\text{C}_2\text{H}_4\)) and oxygen (\(\text{O}_2\)) forming a cyclic peroxide. The diagram represents the molecular structure of ethylene oxide with an oxygen atom attached to a two-carbon chain, forming a triangular ring. - Reaction **(B)** involves the isomerization of normal butane (\(\text{nC}_4\text{H}_{10}\)) to isobutane (\(\text{iC}_4\text{H}_{10}\)), indicated by a bidirectional arrow. This denotes an equilibrium between the two isomers.
Transcribed Image Text:**Problem 3** Write the rate law for the following reactions, assuming each reaction follows an elementary rate law. Give the units of \( k_A \) for each rate law, keeping in mind that some reactions are homogeneous and some reactions are heterogeneous: **(A)** \( \text{C}_2\text{H}_4 + \frac{1}{2} \text{O}_2 \rightarrow \begin{array}{c} \\ O \\ | \\ \text{CH}_2 - \text{CH}_2 \end{array} \) **(B)** \( \text{nC}_4\text{H}_{10} \rightleftharpoons \text{iC}_4\text{H}_{10} \) **Explanation of Diagram:** - Reaction **(A)** involves ethylene (\(\text{C}_2\text{H}_4\)) and oxygen (\(\text{O}_2\)) forming a cyclic peroxide. The diagram represents the molecular structure of ethylene oxide with an oxygen atom attached to a two-carbon chain, forming a triangular ring. - Reaction **(B)** involves the isomerization of normal butane (\(\text{nC}_4\text{H}_{10}\)) to isobutane (\(\text{iC}_4\text{H}_{10}\)), indicated by a bidirectional arrow. This denotes an equilibrium between the two isomers.
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