13. A steel rod of 20 mm diameter passes centrally through a copper tube of external diameter 40 mm andinternal diameter 20 mm. The tube is closed at each end with the help of rigid washers (of negligiblethickness) which are screwed by the nuts. The nuts are tightened until the compressive load on thecopper tube is 50 kN. Determine the stresses in the rod and the tube, when the temperature of wholeassembly falls by 50°C. Take E, = 200 GPa ; E̟ = 100 GPa ; a, = 12 x 106°C and a = 18 x 10/°C.[Ans. 99.6 MPa; 19.8 MPa]14. A bar of 2 m length, 20 mm breadth and 15 mm thickness is subjected to a tensile load of 30 kN.Find the final volume of the bar, if the Poisson's ratio is 0.25 and Young's modulus is 200 GN/m².[Ans. 600 150 mm³]A bar of 12 mm diameter gets stretched by 3 mm under a steady load of 8 kN. What stress would beproduced in the bar by a weight of 800 N, which falls through 80 mm before commencing the stretch-ing of the rod, which is initially unstressed. Take E= 200 kN/mm2.15.[Ans. 170.6 N/mm?]

Since the question containes multiple questions. I am answering only one question (15) only. So,…

15. A bar of 12 mm diameter gets stretched by 3 mm under a steady load of 8 kN. What stress would be produced in the bar by a weight of 800 N, which falls through 80 mm before commencing the stretch- ing of the rod, which is initially unstressed. Take E = 200 kN/mm². [Ans. 170.6 N/mm²]

15. A bar of 12 mm diameter gets stretched by 3 mm under a steady load of 8 kN. What stress would be produced in the bar by a weight of 800 N, which falls through 80 mm before commencing the stretch- ing of the rod, which is initially unstressed. Take E = 200 kN/mm². [Ans. 170.6 N/mm²]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Can you please answer question B, thank you
!
An aluminum [E-9600 ksi] control rod with a circular cross section must not stretch more than 0.34 in. when the tension in the rod is 2070 lb. If the maximum allowable normal stress in the rod is 12.9 ksi, determine: (a) the smallest diameter d that can be used for the rod. (b) the corresponding maximum length L of the rod. Answers: (a) d- i in. (b) L- in.
D- EVEN: The following data are taken from a 25mm in diameter bar of length 250mm, the following results were recorded. Assume that the curve of the stress-strain diagram is linear from the origin to the first point. P (load in kN) 8(elongation in mm) 0.2 0.3 112 154 167 0.4 0.5 0.6 174 181 Determine the a. Stress at 167 KN load in MPa b. Strain at 167 kN load in mm/mm (expressed in scientific notation) c. Modulus of elasticity MPa d. Modulus of resilience in N-mm/mm3 e. Modulus of toughness in N-mm/mm3
Please don't provide handwritten solution ......
Please answer ASAP in 3 decimal places, need within an hour, thank you!
Q7 For the bracket shown in the figure: > The moment of the force (1000N) about pin A is...... > The moment of the force (1000N) about pin B is...... The moment of the force (1000N) about pin C is. 600mm 1000 N 500mm 200mm 240 N.m CCW, 562 N.m CCW, 1099 N.m CCW 200 N.m CW, 468 N.m CW, 915 N.m CW 562 N.m CW, 1099 N.m CW, 240 N.m CW 468 N.m CW, 915 N.m CW, 200 N.m CW O GOOD LUCK! Eiminer Asst. Lecturer. Reem Al-Timimi Head of the Department Dr. Hussein Sadig
B) Two plates joined with straps and a single row of two rivets (or bolts). Rivets have a diameter of d=10 mm and all made of ductile steel having yield strengths in shear of ty = 160 MPa. What force (F) in kN can be transmitted across the joint based on rivet shear strength, take F.S=2 ? %3D Rivet diameter = 10 mm
In a sheet metal of 2 mm thickness, a hole of 10 mm diame- ter needs to be punched. The yield strength in tension of the sheet material is 100 MPa and its ultimate shear strength is 80 MPa. The force required to punch the hole (in kN) is
Don't Copy, I need correct solution within 10-20minutes. Please do it fast. [Handwritten recommended]
What force is required in Newton to punch a 30-mm diameter hole in a plate that is 15 mm thick? The shear strength is 350 MN/m^2. question 2: A type of stress that acts coplanar with cross section of material.
In the max shear stress equation for torsion, the value of c for a rod of diameter = 0.05m is