140 moles of a gas which has y = 1.31 expands from Vi = 0.5m³ to = 1.8m³ following the relation P(V) = 2.0 × 10³ Pa m³ / +1 +1.2 x 105. Pa. m³ V (2)
140 moles of a gas which has y = 1.31 expands from Vi = 0.5m³ to = 1.8m³ following the relation P(V) = 2.0 × 10³ Pa m³ / +1 +1.2 x 105. Pa. m³ V (2)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:140 moles of a gas which has y = 1.31 expands from V₂ = 0.5m³ to
Vf = 1.8m³ following the relation
P(V) = 2.0 × 105 Pa
Pa
m³-
m³1/1/ +1.2 x 105:
m³
30. What is Cv, the molar specific heat at constant volume, for this gas?
(a) 1.3R
(b) 2.3R
(c) 3.2R
(d) 4.2R
(e) 5.2R
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