A sealed 99 m3 tank is filled with 6000 moles of ideal oxygen gas (diatomic) at an initial temperature of 270 K. The gas is heated to a final temperature of 320 K. The atomic mass of oxygen is 16.0 g/mol. The mass density of the oxygen gas, in Sl units, is closest to:

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### Question 7

A sealed 99 m³ tank is filled with 6000 moles of ideal oxygen gas (diatomic) at an initial temperature of 270 K. The gas is heated to a final temperature of 320 K. The atomic mass of oxygen is 16.0 g/mol. The mass density of the oxygen gas, in SI units, is closest to:

- 3.9
- 1.9
- 1.5
- 2.4
- 0.97

#### Explanation:
To determine the closest mass density of the oxygen gas, you can use the data provided from the problem.

For reference: 

\[
\text{Density} (\rho) = \frac{\text{mass}}{\text{volume}}
\]

Mass can be calculated using the number of moles and the atomic mass:

\[
\text{Mass} = \text{moles} \times \text{molecular mass}
\]

Given:
- Volume \( V = 99 \, m^3 \)
- Moles \( n = 6000 \) moles
- Molecular mass of O\(_2\) (since it is diatomic) = \( 2 \times 16 = 32 \, g/mol = 0.032 \, kg/mol \)

So, the mass of the gas is:

\[
\text{Mass} = 6000 \, \text{moles} \times 0.032 \, \text{kg/mol} = 192 \, \text{kg}
\]

Finally, density is:

\[
\rho = \frac{192 \, \text{kg}}{99 \, m^3} \approx 1.939 \, kg/m^3
\]

The closest value to this result is 1.9, so the correct answer is:
- 1.9
Transcribed Image Text:### Question 7 A sealed 99 m³ tank is filled with 6000 moles of ideal oxygen gas (diatomic) at an initial temperature of 270 K. The gas is heated to a final temperature of 320 K. The atomic mass of oxygen is 16.0 g/mol. The mass density of the oxygen gas, in SI units, is closest to: - 3.9 - 1.9 - 1.5 - 2.4 - 0.97 #### Explanation: To determine the closest mass density of the oxygen gas, you can use the data provided from the problem. For reference: \[ \text{Density} (\rho) = \frac{\text{mass}}{\text{volume}} \] Mass can be calculated using the number of moles and the atomic mass: \[ \text{Mass} = \text{moles} \times \text{molecular mass} \] Given: - Volume \( V = 99 \, m^3 \) - Moles \( n = 6000 \) moles - Molecular mass of O\(_2\) (since it is diatomic) = \( 2 \times 16 = 32 \, g/mol = 0.032 \, kg/mol \) So, the mass of the gas is: \[ \text{Mass} = 6000 \, \text{moles} \times 0.032 \, \text{kg/mol} = 192 \, \text{kg} \] Finally, density is: \[ \rho = \frac{192 \, \text{kg}}{99 \, m^3} \approx 1.939 \, kg/m^3 \] The closest value to this result is 1.9, so the correct answer is: - 1.9
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