A sealed 73 m tank is filled with 8000 moles of ideal oxygen gas (diatomic) at an initial temperature of 270 K. The gas is heated to a final temperature of 390 K. The atomic mass of oxygen is 16.0 g/mol. The mass density of the oxygen gas, in Sl units, is closest to: O 7.0 O 4.4 O 2.6 О 35 O 1.8
A sealed 73 m tank is filled with 8000 moles of ideal oxygen gas (diatomic) at an initial temperature of 270 K. The gas is heated to a final temperature of 390 K. The atomic mass of oxygen is 16.0 g/mol. The mass density of the oxygen gas, in Sl units, is closest to: O 7.0 O 4.4 O 2.6 О 35 O 1.8
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![**Determination of Oxygen Gas Mass Density in SI Units**
**Problem Statement:**
A sealed 73 m³ tank is filled with 8000 moles of ideal oxygen gas (diatomic) at an initial temperature of 270 K. The gas is heated to a final temperature of 390 K. The atomic mass of oxygen is 16.0 g/mol. The mass density of the oxygen gas, in SI units, is closest to:
- 7.0
- 4.4
- 2.6
- 3.5
- 1.8
**Multiple Choice:**
- O 7.0
- O 4.4
- O 2.6
- O 3.5
- O 1.8
**Instructions:**
Click Save and Submit to save and submit. Click Save All Answers to save all answers.
---
**Educational Notes:**
To solve for the mass density of the oxygen gas, follow these steps:
1. **Determine the total mass of oxygen gas in the tank:**
- The molecular mass of O₂ gas (diatomic) is \( M = 2 \times 16.0 \text{ g/mol} = 32.0 \text{ g/mol} \).
- The total mass \( m \) of the gas is given by the number of moles \( n \) multiplied by the molecular mass \( M \):
\[
m = n \times M = 8000 \text{ moles} \times 32.0 \text{ g/mol} = 256000 \text{ g} = 256 \text{ kg}
\]
2. **Calculate the mass density \( \rho \):**
- The volume \( V \) of the tank is 73 m³.
- The mass density \( \rho \) is the mass \( m \) divided by the volume \( V \):
\[
\rho = \frac{m}{V} = \frac{256 \text{ kg}}{73 \text{ m}^3} \approx 3.5 \text{ kg/m}^3
\]
Thus, the closest answer for the mass density of the oxygen gas in SI units is **3.5 kg/m³**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8689a897-6f19-4f8c-bce2-bc1e854b9491%2Faf49141a-4396-4bfe-af8e-82a8bdf785de%2F0eiwuw.jpeg&w=3840&q=75)
Transcribed Image Text:**Determination of Oxygen Gas Mass Density in SI Units**
**Problem Statement:**
A sealed 73 m³ tank is filled with 8000 moles of ideal oxygen gas (diatomic) at an initial temperature of 270 K. The gas is heated to a final temperature of 390 K. The atomic mass of oxygen is 16.0 g/mol. The mass density of the oxygen gas, in SI units, is closest to:
- 7.0
- 4.4
- 2.6
- 3.5
- 1.8
**Multiple Choice:**
- O 7.0
- O 4.4
- O 2.6
- O 3.5
- O 1.8
**Instructions:**
Click Save and Submit to save and submit. Click Save All Answers to save all answers.
---
**Educational Notes:**
To solve for the mass density of the oxygen gas, follow these steps:
1. **Determine the total mass of oxygen gas in the tank:**
- The molecular mass of O₂ gas (diatomic) is \( M = 2 \times 16.0 \text{ g/mol} = 32.0 \text{ g/mol} \).
- The total mass \( m \) of the gas is given by the number of moles \( n \) multiplied by the molecular mass \( M \):
\[
m = n \times M = 8000 \text{ moles} \times 32.0 \text{ g/mol} = 256000 \text{ g} = 256 \text{ kg}
\]
2. **Calculate the mass density \( \rho \):**
- The volume \( V \) of the tank is 73 m³.
- The mass density \( \rho \) is the mass \( m \) divided by the volume \( V \):
\[
\rho = \frac{m}{V} = \frac{256 \text{ kg}}{73 \text{ m}^3} \approx 3.5 \text{ kg/m}^3
\]
Thus, the closest answer for the mass density of the oxygen gas in SI units is **3.5 kg/m³**.
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